When k changes, all the lines pass through the fixed point A（0,0） B（0,1） C（3,1） D（2,1）

When k changes, all the lines pass through the fixed point A（0,0） B（0,1） C（3,1） D（2,1）

kx-y+1-3k=0
k(x-3)-y+1=0
When x = 3, no matter what value K takes in the above formula, it does not affect the value of Y (any number multiplied by 0 is 0), then y = 1
So hengguo (3,1)
Choose C

When k changes, all the lines pass through the fixed point ()
A. （0，0）B. （0，1）C. （3，1）D. （2，1）

From kx-y + 1 = 3k, K (x-3) = Y-1 holds for any k ∈ R, then x − 3 = 0, y − 1 = 0, the solution is x = 3, y = 1, so the line passes through the fixed point (3, 1), so C