A cube box can just put a cylinder with a volume of 628 cubic centimeters. How many cubic centimeters is the volume of this box?

A cube box can just put a cylinder with a volume of 628 cubic centimeters. How many cubic centimeters is the volume of this box?

zdsjwy1,
Analysis: cylinder volume = 3.14 × edge length / 2 × edge length / 2 × edge length = 3.14 △ 4 × cube volume
628 ^ (3.14 ^ 4) = 800 (cm3)

A cube box can hold a 628 cubic centimeter cylinder. What is the volume of the box?

This cylinder is an equilateral cylinder with d = 2R = h and the side length of the square is also H
V-column = π * D & sup2 / 4 * H = 628
D²*H=800
H³=800
V square = H & sup3; = 800cm & sup3;

A cube box can hold a cylinder with a volume of 628 cubic centimeters. Please find out the volume of the box?

pir^2/(2r)^2=628/V
(pi = 3.14)
3.14/4=628/V
V=4*200=800cm^3

A cube box can just hold a cylinder with a volume of 628 cubic centimeters. What's the volume of this box?
It's urgent. It's urgent
Better not be an equation

397758730,
Analysis: cylinder volume = 3.14 × edge length / 2 × edge length / 2 × edge length = 3.14 △ 4 × cube volume
Box volume: 628 ^ (3.14 ^) 4 = 800 (cm3)

The line y = 2 / 3x-3 intersects the x-axis and y-axis with a and B respectively, and O is the origin
(1) Find the area of △ AOB (2) can you draw a straight line through the vertex of △ AOB? Divide △ AOB into two parts with equal area? If you can, how many can you draw? Write such a straight line analytical formula

Let x = 0, y = 0, respectively, and the analytic formula of the generation line obtain the coordinates of a and B. the area of B (0, - 3), a (9 / 2,0) ∧ △ AOB = ∧ 189; × 3 × 9 / 2 = 27 / 4 are the midlines on each side respectively. Then each midline divides the area of △ AOB into two equal parts. There are three midlines

Let C (x, y) be the point of y = 2X-4 in the first quadrant,
Connect BC to Y-axis point E
1. Find out the analytic formula of the area s of △ ABC with respect to x, and write out the value range of the independent variable x
2. When AC = √ 5ab, calculate the area of quadrilateral oace
3. Let C (x, y) be a point on the straight line y = 2X-4, and point d be on the Y axis. To make the quadrilateral with points a, B, C and D as its vertex a parallelogram, please write out the coordinates of point C directly

1. Let C (x1, Y1), because point C is on the straight line y = 2X-4, Y1 = 2x1-4, from the meaning of the title, we can easily get a (2,0), B (- 2,0), s (△ ABC) = 1 / 2 * | ab | * | Y1 |, and point C is the point of the straight line in the first quadrant, so Y1 > 0, s (△ ABC) = 1 / 2 * 4 * (2x1-4) = 4x1-8 (x1 > 2) 2. AB = 4, so AC = 4 √ 5

The line y = 2x - 4 intersects the X axis and Y axis at two points a and B respectively, and O is the dot
1) Calculate the area of Δ AOB;
(2) Can we draw a straight line through the vertex of Δ AOB and divide Δ AOB into two parts with equal area? If so, how many can we draw? Write the corresponding functional relationship of such a straight line

1.
Find the intersection point
When y = 0, x = 2, that is a (2,0)
When x = 0, y = - 4, that is B (0, - 4)
So s Δ AOB = OA * ob / 2 = 4
two
Each vertex can be made one, a total of 3
If the intersection point is e, then Δ AOE and the bottom OA of Δ AOB are equal, so the height of Δ AOE is half of the height of Δ AOB, the height of Δ AOB is 4, so the height of Δ AOE is 2. In the negative half axis of Y axis, the ordinate of intersection point E is - 2, the abscissa is - 2 = 2X-4, x = 1, that is e (1, - 2)
Substituting e into y = KX, k = - 2
That is y = - 2x
Passing point A:
Let y = K1X + B, intersect with y axis at f point, we know that of is the height of Δ AOF, so f (0, - 2)
Substituting, we get - 2 = B
Substituting point a into 0 = 2k1-2, K1 = 1
That is y = X-2
Passing point B:
Let y = k 2x + B, intersect with X axis at H point, we can know that the coordinate of H point is: (1,0) the same as above
Substituting h and B
-4=B
0=K2+B
B=-4,K2=4
So y = 4x-4

The line y = 2x + 4 intersects the x-axis at a and the y-axis at B. point C and point D are the symmetrical points of a and B about the origin respectively. (1) find the analytical expression of the line CD. (2) find the four sides of the line
2) Finding the area of four sides of ABCD

A(-2,0)、B(0,4)、C(2,0)、D(0,-4)
According to the coordinates of points c and D, the
2a+b=0
0a+b=-4
So the analytic formula is y = 2X-4
The area is composed of four right triangles, s = 2 * 4 / 2 * 4 = 4

Let the line AB tangent to the circle x ^ 2 + y ^ 2-2x-2y + 1 = 0 intersect the X axis, and the Y axis intersects a and B respectively
Let a (a, 0), B (0, b), and a > 2, b > 2, find the minimum area of △ AOB

It is known that the line L intersects the x-axis and y-axis at points a (a, 0) and B (0, b), and is tangent to the circle C: x ^ 2 + y ^ 2-2x-2y + 1 = 0, (where a > 2, b > 2)
Q: (1) what conditions should a and B meet
(2) Finding the minimum length of line ab