Let a (- 1,0) B (1,0) line L1 and L2 pass through two points a and B respectively, and the product of slope is - 4

Let a (- 1,0) B (1,0) line L1 and L2 pass through two points a and B respectively, and the product of slope is - 4

Let L1 y = K1 (x-1) L2 y = K2 (x + 1) K1 = Y / (x-1) K2 = Y / (x + 1) K1 * K2 = - 4, y = - 4 (x-1) intersection C: Y / 4 + x = 1 be an elliptic equation

If the intersecting lines L1 and L2 cross points a (- 5,0) and B (5,0) respectively, and the product of the slopes of L1 and L2 is - 4 / 9, the trajectory equation of the intersection of L1 and L2 is obtained, and its shape is pointed out

4x^2+9y^2=100

Given the points a (- 3,2) and B (1, - 4), make two mutually perpendicular lines L1 and L2 through a and B, then the trajectory equation of the intersection m of L1 and L2 is______ &Nbsp; (in standard form)

Let m (x, y), then make the intersection m of two mutually perpendicular straight lines L1 and L2 through a and B, Ma · MB = 0, {(- 3-x, 2-y) · (1-x, - 4-y) = 0,} (- 3-x) (1-x) + (2-y) (- 4-y) = 0, and (x + 1) 2 + (y + 1) 2 = 13. So the answer is: (x + 1) 2 + (y + 1) 2 = 13

If the line L1: y = 2x + 3, the lines L2 and L1 are symmetric with respect to the line y = x, the slope of the line L2 is obtained

Just swap X and y
Line L1: y = 2x + 3, line L2 and line L1 are symmetric with respect to line y = X
The line L2 is x = 2Y + 3
That is, y = x / 2-3 / 2