If 1 / 24 is equal to one part of a plus one part of B, and a and B are two different natural numbers, then the sum of a and B is the smallest
First, list the factors of 24
The factors of 24 are: 1, 2, 3, 4, 6, 8, 12, 24
Then multiply the numerator and denominator of 1 / 24 by the sum of the two coprime numbers of these factors at the same time to get the form of adding two different fractional units
Finally, we can get what we want
1/24=1*(1+2)/24*(1+2)=(1+2)/(24*3)=1/72+1/36
1/24=1*(1+3)/24*(1+3)=(1+3)/(24*4)=1/96+1/32
……
I won't list them all
The smallest should be the sum of the two prime numbers to get a different fractional unit, i.e
1/24=1*(2+3)/24*(2+3)=1/60+1/40
So the minimum of a + B is 60 + 40 = 100
24 minus 19?
24-19=5
5 × (5 / 7 minus 1 / 5) = () - () equals ()
5 × (5 / 7 minus 1 / 5)
=(5 / 5x7) - (1 / 5x5)
=18 out of 7
A few minus ten times ten divided by ten equals ten
20
Eight thirds is equal to twenty-four percent, how much is equal to twenty-four percent, how much is equal to forty percent
Eight thirds equals sixty-four of twenty-four. Twenty four of nine, 266.7 percent
It's too simple. 8 / 3, divide 24 by 3 = 8, so the denominator × 8, the molecule should also be × 8, so = 64 / 24, OK?
-How can 3 3 - 8 8 be equal to 24
(-8)÷(-3+3÷8)=24
How to calculate 9.28 times 13 minus 9.28 times 4 plus 9.28
9.28x13-9.28x4+9.28
=9.28x(13-4+1)
=9.28x10
=92.8
How to calculate 13 / 17 * 5 / 9 + 4 / 17 * 13 / 9?
13/17*5/9+4/17*13/9
=13/17*1/9(5+4)
=13/17*1/9*9
=13/17
Calculation: one sixth plus one twelfth plus one twentieth What's one tenth of nine?
According to: one sixth equals one half minus one third, one twelfth equals one third minus one fourth, one twentieth equals one fourth minus one fifth
According to the prompt,
Original formula = (1 / 2 - 1 / 3) + (1 / 3 - 1 / 4) + (1 / 4 - 1 / 5) + (1 / 5 - 1 / 6) + (1 / 6 - 1 / 7) + (1 / 7 - 1 / 8)+
( 1/8 - 1/9 ) + ( 1/9 - 1/10 )
= 1/2 - 1/10
= 2/5
Three quarters plus one sixth is equal to?
3/4+1/6=11/12