Let f (x) = | lgx |, a and B be real numbers satisfying f (a) = f (b) = 2F ((a + b) / 2), where 0

Let f (x) = | lgx |, a and B be real numbers satisfying f (a) = f (b) = 2F ((a + b) / 2), where 0

(1) Because a is not equal to B, so LGA is not equal to LGB, and | LGA | = | LGB |, must be LGA = - LGB = LG (1 / b), get a = 1 / B, because 0

Let f (x) = 1 + lgx, G (x) = x ^ 2, then the x value of 2F [g (x)] = g [f (x)] is 10 ^ (1 + radical 2) and 10 ^ (1-radical 2)
Let f (x) = 1 + lgx, G (x) = x ^ 2, then the x value of 2F [g (x)] = g [f (x)] is
The answer is 10 ^ (1 + radical 2) and 10 ^ (1-radical 2)

Because f (x) = 1 + lgx, G (x) = 1 + lgx, G (x) = 1 + lgx, G (x) = 1 + lgx, G (x) = 1 + lgx, G (x) = 1 + lgx, G (x) = 1 + lgx, G (x) = 1 + lgx, G (x) = 1 + lgx, G (x) = 1 + lgx (1 + lgx) = (1 + lgx) = (1 + 2 lgx + lgx + lgx + 1 + lgx + 1 + lgx + lgx + lgx \\\\\\\\\\\\\\\\\\\\\\\\\\\x = (2 ±

F (x) = | lgx |, a, B satisfy that f (a) = f (b) = 2F [(a + b) / 2], and 0

F (a) = f (b) = 2F [(a + b) / 2] and 01, but AB = 1, so B = 1 / A