Lgx-1 / x = 0 is a (0.1] B (1.10) C (10.100) d (100. Positive infinity)

Lgx-1 / x = 0 is a (0.1] B (1.10) C (10.100) d (100. Positive infinity)


This is about finding zero
lg1-1/1=-10
So the region is B (1.10]



If lgx + lgx ^ 2 + lgx ^ 3 +. + lgx ^ 10 = 100, then lgx + (lgx) ^ 2 + (lgx) ^ 3 +. + (lgx) ^ 10=


lgx+lgx^2+lgx^3+.+lgx^10=lg(x*x^2*…… *x^10)=lg[x^(1+2+…… +10) ] = 55lgx = 100lgx = 20 / 11, so lgx + (lgx) ^ 2 + (lgx) ^ 3 +. + (lgx) ^ 10 = = 20 / 11 * [1 - (20 / 11) ^ 10] / (1-20 / 11) = 20 / 9 * [(20 / 11) ^ 10-1]

Elden Ring Premiere

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