Given the points (2,8) and B (6, - 4), find a point m on the x-axis such that Ma = MB, and find the coordinates of point M

Given the points (2,8) and B (6, - 4), find a point m on the x-axis such that Ma = MB, and find the coordinates of point M

Let me tell you the main point directly, m coordinate is (x, 0). Then use the distance formula between two points, the two distances are equal. Then we can list the equation containing x, and the square of X will be reduced. Finally, we get that x is equal to 2

Given that a and B are two of the equations x2 + (M + 2) x + 1 = 0, then the value of (A2 + Ma + 1) (B2 + MB + 1) is______ ．

∵ a, B are two of the equations x2 + (M + 2) x + 1 = 0, ∵ a + B = - (M + 2), ab = 1, A2 + (M + 2) a + 1 = 0, B2 + (M + 2) B + 1 = 0, ∵ A2 + 1 = - (M + 2) a, B2 + 1 = - (M + 2) B, ∵ A2 + Ma + 1) (B2 + MB + 1) = [- (M + 2) a + Ma] [- (M + 2) B + MB] = (- 2A) · (- 2b) = 4AB = 4 × 1 = 4