As shown in the figure, in rectangular ABCD, diagonal lines AC and BD intersect at point O, ∠ BOC = 120 ° AB = 6, find: (1) the length of diagonal line; (2) the length of BC; (3) the area of rectangular ABCD

As shown in the figure, in rectangular ABCD, diagonal lines AC and BD intersect at point O, ∠ BOC = 120 ° AB = 6, find: (1) the length of diagonal line; (2) the length of BC; (3) the area of rectangular ABCD


(1) The ∵ quadrilateral ABCD is a rectangle, ∵ OA = ob = 12bd. The ∵ BOC = 120 °, the ∵ AOB = 60 °, the ∵ AOB is an equilateral triangle, ∵ ob = AB = 6, ∵ the length of the diagonal BD is BD = 2ob = 12; (2) from (1) we know that the diagonal length of the rectangular ABCD is 12, then AC = 12. In the right angle ∵ ABC, ab = 6, AC = 12, then from the Pythagorean theorem, BC = ac2 − AB2 = 63; (3) in the rectangular ABCD, ab = 12 =6, BC = 63, then the area of the rectangle = ab · BC = 6 × 63 = 363



It is known that in rectangular ABCD, the diagonal AC and BD intersect at O, the angle BOC equals 120 ° and AC equals 4cm
Finding area and perimeter


Because the angle BOC = 120 degrees
So AOB = 60 degrees
The diagonals of the rectangles are equal and equally divided
So delta AOB is an equilateral triangle
Because AC = 4
So AB = 2, AC = 2 √ 3
So the circumference of the rectangle = (4 + 4 √ 3) cm
The area is 4 √ 3 square centimeter



It is known that, as shown in the figure, the two diagonal lines AC and BD of rectangle ABCD intersect at the point O, ∠ BOC = 120 degrees, ab = 4cm, and the length of rectangle diagonal line is calculated


Therefore, the triangle AOB is an equilateral triangle, OA = ob = AB = 4
The diagonal equals eight



If a rectangle ABCD with a circumference of 56, O is the intersection of the diagonal, and the difference between the circumference of △ BOC and △ AOB is 4, then AB =, BC =
If a rectangle ABCD with a circumference of 56, O is the intersection of the diagonal, and the difference between the circumference of △ BOC and △ AOB is 4, then AB =, BC =


If BC > AB, perimeter = 4 * AB + 4 * 2 = 56, ab = 12, CD = 16, and vice versa