Given the set a = {a, a + D, a + 2D}, B = {a, AQ, AQ & sup2;}, (a is a known constant), if a = B, find the value of D, Q

Given the set a = {a, a + D, a + 2D}, B = {a, AQ, AQ & sup2;}, (a is a known constant), if a = B, find the value of D, Q


If: a + D = aq. 1) a + 2D = AQ ^ 2.2) 1) * 2-2) get: a = 2aq-aq ^ 2A (Q ^ 2-2q + 1) = 0A (Q-1) ^ 2 = 0q = 1, then a = AQ = AQ ^ 2, impossible if: a + D = AQ ^ 2A + 2D = AQ, solve the equations: q = 1, d = 0, (add root, round off) q = - 1 / 2, d = - 3A / 4, so, q = - 1 / 2, d = - 3A / 4



Three big balls with one radius are tangent to each other and placed on the table top. A small ball is placed between the table top and the three big balls. The small ball is tangent to the table top and the three big balls. The radius of the rigid small ball is?


2√3/3-1



The known set a = {x | 3


(1) ∵ x-m < 0 ∩ x < m ∩ a ∩ B = empty set ∩ m ≤ 3 (2) 2 it's very different whether it contains B or B. if it contains B, it means that the value range of X in B is large ∵ a contains B ∩ m ≥ 5. If it contains B, it means that there are more set elements in a than in B, but it can't be calculated



Given the set a = {(x, y) | x ^ 2 + mx-y + 2 = 0}, B = {(x, y) | X-Y., find the value range of real number M
The known set a = {(x, y) | x ^ 2 + mx-y + 2 = 0}, B = {(x, y) | X-Y + 1 = 0, 0


If a intersects B is not an empty set, then the equation x ^ 2 + MX - (x + 1) + 2 = 0 has a solution on [0,2]
Let the equation be [x + (m-1) / 2] ^ 2 + 1 - (m-1) ^ 2 / 4 = 0, and let the function y = [x + (m-1) / 2] ^ 2 + 1 - (m-1) ^ 2 / 4 [combined with graph]
When - (m-1) / 2 = 1, if there is a solution on [0,2], then y (0) = 0, obviously y (0) = 1 > 0 is not satisfactory;
When - (m-1) / 2 > = 2, that is, M = 0 and Y (2)