It is known that three line segments are 10, 14 and 20 long respectively. Two of them are diagonals, and the other one can draw a parallelogram

Analysis and discussion: it is known that the lengths of three line segments are 22cm, 16cm and 18cm respectively. Which two line segments are diagonals, and the other one is an edge to draw a parallelogram
Furthermore, if a, B are diagonals and C are parallelograms, what is the relationship between a, B and C? (a is greater than B)

The parallelogram can be drawn with 22cm, 16cm as diagonal and 18cm as side
Taking 22cm, 18cm as diagonals and 16cm as sides, parallelogram can also be drawn
Taking 16cm, 18cm as diagonals and 22cm as sides can't draw parallelogram
`
If a and B are diagonals (a is greater than B), and C is one side of the parallelogram, the relationship between a, B and C should meet the following requirements:
a+b＞2c

One side of a parallelogram is 14, and the length of its two diagonals can be ()
A. 12，16B. 20，22C. 10，16D. 14，12

This side of the parallelogram and half of the two diagonals form a triangle. Only 222-202 ＜ 14 ＜ 222 + 202, i.e. 1 ＜ 14 ＜ 21, can a triangle be formed if the third side is greater than the difference between the two sides and less than the sum of the two sides

The length of one side of a parallelogram is equal to 14 cm. Which group of data can its diagonal length be? A 10 and 16 B 12 and 16 C 20 and 22 D 10 and 40

Prove with vector method: parallelogram with equal diagonal is rectangle

Because it's a parallelogram
ab+bc=ac bc+cd=bd
Because | AC | = | BD|
So (AB + BC) ^ 2 = (BC + CD) ^ 2
ab^2+bc^2+2ab*bc=bc^2+cd^2+2bc*cd
Because AB ^ 2 = CD ^ 2, BC ^ 2 = ad ^ 2
So angle ABC = angle BCD = 90 degrees

How to prove that a parallelogram with equal diagonals is a rectangle! I've drawn the diagram, and help me to solve it. I want to prove it in detail. It's better to prove that △ AOD and △ BOC are congruent! Thank you, OK

In parallelogram ABCD, AC = BD is characterized by parallelogram: opposite sides are equal: BC = ad, ab = AB, so: △ ABC ≌ Δ bad shows that: ∠ ABC = ∠ bad, and ∠ ABC + ∠ bad = 180 ° so: ∠ ABC = ∠ bad = 90 °, that is, an angle of parallelogram is a right angle, so ABCD is a rectangle ∠ a = 90 °, and ∠ B = 90 °, Because: ∠ a + B + C + D = 360 °, so: ∠ d = 360 °－ a - B - C = 360 °－ 90 °－ 90 ° = 90 °, that is, the four corners of the quadrilateral ABCD are right angles, so ABCD is a rectangle

Prove that a parallelogram with equal diagonals is a rectangle

It is known that the quadrilateral ABCD is a parallelogram, AC and BD are two diagonals, and AC = BD. prove that the parallelogram ABCD is a rectangle. Prove that, as shown in the figure, ∵ quadrilateral ABCD is a parallelogram, ∵ AB = DC, ab ∥ DC. In △ ABC and △ DCB, ab = DCAC = bdbc = CB, ≌ ABC ≌ DCB (SSS). ≌ ABC = ≌ DCB. And ≂ ABC + ∥ DCB = 180 ° and ≌ ABC = ≌ DCB = 90 ° The parallelogram ABCD is a rectangle

Prove that a parallelogram with equal diagonals is a rectangle

It is known that the quadrilateral ABCD is a parallelogram, AC and BD are two diagonals, and AC = BD. prove that the parallelogram ABCD is a rectangle. Prove that, as shown in the figure, ∵ quadrilateral ABCD is a parallelogram, ∥ AB = DC, ab ∥ DC. In △ ABC and △ DCB, ab = DCAC = bdbc = CB, ≌ ABC ≌ △ DCB (SSS

It is known that three line segments are 10, 14 and 20 long respectively. Two of them are diagonals, and the other one can draw a parallelogram