The quadratic form f (x1, X2, x3) = X1 square - x2 square + x1x2 was formulated as the standard form

The quadratic form f (x1, X2, x3) = X1 square - x2 square + x1x2 was formulated as the standard form

f = (x1+(1/2)x2)^2 - (1/4)x2^2 -x2^2
= (x1+(1/2)x2)^2 - (5/4)x2^2
= y1^2 - 5/4y2^2

Mathematical binary linear equation - 2Y = - 2x y = - x + 2
Please write down the detailed process,

-2Y=-2X => Y=X
Y=-X+2 => Y=-Y+2 => Y+Y=2 => Y=1 => X=1

The quadratic equation of two variables, 2x ＋ y = 1 x ＋ 2Y = 3 (important process) is very fast
The linear equation of three variables, x + 2Y + Z = 1 2x + 3Y + Z = 2 3x + 4Y + 2Z = 6

If 2x + y = 1 2x + 5Y = 5 (1) x + 2Y = 3 7x + 2Y = 14 (2) (2) * 5 - (1) * 2, 31x = 60x = 60 / 31 is substituted by (1) 120 / 31 + 5Y = 5Y = 7 / 31x + 2Y + Z = 1 (1) 2x + 3Y + Z = 2 (2) 3x + 4Y + 2Z = 6 (3) (2) - (1), x + y = 1 (4) (2) * 2 - (3), x + 2Y = - 2 (x +

When x = - 1 / 2, the bivariate linear equation 2x-y = 3 has the same solution as KX + 2Y = - 1, then k = (to complete the process,

When x = - 1 / 2, the bivariate linear equation 2x-y = 3 has the same solution as KX + 2Y = - 1, then
y=2x-3=-4
-k/2-8=-1
k=-14

8x+4y=25 5/2x-9/2y=10

8x+4y=25 (1)
5/2x-9/2y=10
Double two on both sides
5x-9y=20 (2)
(1)*9+(2)*4
72x+20x=225+80
92x=305
x=305/92
y=(5x-20)/9=-35/92

Is {x + 2Y = 5 2x + 4Y = 10} a system of linear equations with two variables?

Yes, binary means X and Y. because there are two equations (more than one), it is a system of equations, so it is a system of quadratic equations

To solve the linear equation parallel to the line L: 3x-4y + 5 = 0 and the distance is 1

3x-4y+5=0
y=(3/4)x+(5/4)
tga=k=3/4
cosa=4/5=1/m
m=5/4
y=(3/4)x+(5/4+5/4)=(3/4)x+10/4)
y=(3/4)x+(5/4-5/4)=(3/4)x
The equation of the line parallel to the line L: 3x-4y + 5 = 0 and the distance is 1
3x-4y+10=0
3x-4y=0

Find the equation of the line which is perpendicular to the line 3x-4y-12 = 0 and passes through the origin

The slope of 3x-4y-12 = 0 is 3 / 4
So the slope of the line is - 4 / 3
So, the straight line is y = (- 4 / 3) X

Find the linear equation that passes through the origin and is perpendicular to the line 3x-4y + 5 = 0

The equation is 4x + 3Y = 0
It's very simple to exchange the XY coefficients and take the opposite sign for the coefficients of Y

The distance from the origin to the line 3x + 4y-5 = 0 is
Thanks for the exam

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