5 + 25sinx = 12cos ^ 2x, X is greater than or equal to 0 degrees and less than or equal to 360 degrees, find the sum of all results 5 + 25sinx = 12cos ^ 2x, X is greater than or equal to 0 degrees and less than or equal to 360 degrees, find the sum of all results,

5 + 25sinx = 12cos ^ 2x, X is greater than or equal to 0 degrees and less than or equal to 360 degrees, find the sum of all results 5 + 25sinx = 12cos ^ 2x, X is greater than or equal to 0 degrees and less than or equal to 360 degrees, find the sum of all results,

5 + 25sinx = 12cos ^ 2x12 (SiNx) ^ 2-25sinx-7 = 0 (4sinx + 1) (3sinx-7) = 03sinx-7 = 0sinx = 7 / 3 > 1 there is no solution 4sinx + 1 = 0sinx = - 1 / 4x in the third and fourth quadrant. The end of the angle of the fourth quadrant coincides with arcsin (- 1 / 4) = - arcsin1 / 4. X is greater than or equal to 0 degree and less than or equal to 360 degree, so x = 2 π - ar

27 + 36sinx = 32cos ^ 2x, X is greater than or equal to 0 degrees and less than or equal to 360 degrees, find the sum of all results
32(1-sin^2x)=27+36sinx 32（sinx）^2+36x-5=0 (8sinx-1)(4sinx-5)=0
What's next?

32（sinx）^2+36sinx-5=0
(8sinx-1)(4sinx+5)=0
sinx=1/8,sinx=-5/4
X is greater than or equal to 0 degrees and less than or equal to 360 degrees
SiNx = 1 / 8, there are two solutions
One is arcsin 1 / 8 and the other is π - arcsin 1 / 8
The sum of these two solutions = π
sinx=-5/4

The value of F (x) = a (sin ^ 6x + cos ^ 6x) + B (sin ^ 4x + cos ^ 4x) + 6sin ^ 2xcos ^ 2x is independent of X and equal to 1

f(x)=a(sin²x+cos²x)(sin^4x-sin²xcos²x+cos^4x)+b(sin^4x+cos^4x)+6sin^2xcos^2x=a(sin^4x-sin²xcos²x+cos^4x)+b(sin^4x+cos^4x)+6sin^2xcos^2x=(a+b)(sin^4x+cos^4x)+(6-a)sin^2xco...