The number of zeros of the function y = x & #178; - 3|x-1| - 1 is

The number of zeros of the function y = x & #178; - 3|x-1| - 1 is

The zeros of F (x) = x & # 178; - 3 | X-1 | - 1
That is, the root of X & #178; - 3|x-1| - 1 = 0,
（1）x≥1
Then x & # 178; - 3x + 2 = 0
‖ x = 1 or x = 2
（2）x

If the function f (x) = √ (10x-x & # 178; - 21) + √ (7x-x & # 178; - 10) - A has zero, then the value range of real number a is
Using the knowledge of senior one to solve the problem

Find f (x) = √ (10x-x & # 178; - 21) + √ (7x-x & # 178; - 10) to get the maximum and minimum values, that is, the value range of A,
The most value of the formula, the root of the formula, associated with the distance formula, can be considered to be (x, 0) to the other two fixed-point distance, number shape combination you know the answer. This matter is the only simple way, the author also want to test this

If the function f (x) = 3 * x-x & # 178 is known, and there is only one zero point, then the approximate interval of the zero point is

F (x) = 3 ^ x-x & # 178; it is continuous everywhere in the domain of definition,
f(0)=3^0-0^2=1>0
f(-1)=3^(-1)-(-1)^2=-2/3

Calculate 200-199-178; + 198-178; - 197-178; + +2²-1

200²-199²+198²-197²+… +2²-1=（200²-199²）+（198²-197²）+…… +Note: (a) = (a-b) (a + b) = (200-199) x (200 + 199) + (198-197) x (198 + 197) +. + (2 -...)