If the function f (x) = - x ^ 2 + 4x-1, X belongs to [0, t], and the range is [- 1,3], then the real number T is in the range

If the function f (x) = - x ^ 2 + 4x-1, X belongs to [0, t], and the range is [- 1,3], then the real number T is in the range

When x = 2, f (x) = 3 and f (2) is the maximum of F (x)
When f (x) = - 1, x = 0 or 4
SO 2=

Decomposition factor (x2 + Y2) (x2-2xy + Y2) + x2y2 note: 2 is square

(x²+y²)(x²-2xy+y²)+x²y²
=(x²+y²)²-2xy(x²+y²)+(xy)²
=(x²+y²-xy)²

X 2Y 2 + xy-x 2-y 2 + X + y + 2 factorization,

The original formula = (X & # 178; Y & # 178; - X & # 178; - Y & # 178; + 1) + (XY + X + y + 1)
=[x²(y²-1)-(y²-1)]+[x(y+1)+(y+1)]
=(x²-1)(y²-1)+(x+1)(y+1)
=(x+1)(x-1)(y+1)(y-1)+(x+1)(y+1)
=(x+1)(y+1)[(x-1)(y-1)+1]
=(x+1)(y+1)(xy-x-y+2)

Forget. Ask for help 16x ^ 3Y ^ 3 + 24x ^ 2Y ^ 4-32x ^ 2Y ^ 5
1:45a^3b^3c^3-63a^3b^2c^3+27a^3b^3c-72a^2b^2c^3

16x^3y^3+24x^2y^4-32x^2y^5
=8x^2y^3(2x+3y-4y^2)

Factorization (process) - (2x-y) ^ 2 + 10 (2x-y) - 25 - 6x ^ 2-3x ^ 3-3xy ^ 2 - 32x ^ 3-16x ^ 2-2x

-(2x-y) ^ 2 + 10 (2x-y) - 25 primitive = - [(2x-y) ^ 2-10 (2x-y) + 25] = - (2x-y-5) & #178; - 6x ^ 2y-3x ^ 3-3xy ^ 2 primitive = - 3x (2XY + X & #178; + Y & #178;) = - 3x (x + y) & #178; - 32x ^ 3-16x ^ 2-2x primitive = - 2x (16x & #178; + 8x + 1) = - 2x (4x + 1) & #178;

Factorization factor-X ^ 2y-2xy ^ 2 + y ^ 3

x^2y-2xy^2+y^3
=y(x^2-2xy+y^2)
=y(x-y)(x-y)
=y(x-y)^2
If the question is correct:
-x²y-2xy²+y²
=-y(x²+2x-1)

Factorization (x + y) 2 (X-Y) 2 - (X-Y) (x + y) (x2 + Y2)
It's a process, quick

=(x+y)(x-y)[(x+y)(x-y)-(x²+y²)]
=(x+y)(x-y)(x²-y²-x²-y²)
=-2y²(x+y)(x-y)

Factorization: 1. Y ^ 2-y-12 = 0 2. Y (y + 5) = 24 3. (x + 1) ^ 2 = √ 2 (x + 1) 4. 36x ^ 2 = 9 (x + 1) ^ 25. (x-3) ^ 2-3 (3-x) - 4 = 0

1.y^2-y-12=0 (y-4)(y+3)=0y=4 y=-32.y(y+5)=24y^2+5y-24=0(y-3)(y+8)=0y=3 y=-83 .(x+1)^2=√2(x+1)(x+1)^2-√2(x+1)=0(x+1)(x+1-√2)=0x=-1 x=√2-14 .36x^2=9(x+1)^236x^2-9(x+1)^2=0(6x+3(x+1))(6x-3(x+1))=0(9x...

（x2+x）2-14（x2+x）+24．

The original formula = (x2 + x-3) (x2 + X-8) = (x + 2) (x-1) (x + 4) (x-3)

Factorization (- 2) ^ 2009 + (- 2) ^ 2010

(-2)^2009+(-2)^2010
=(-2)^2009+(-2)×(-2)^2009
=(-2)^2009(1-2)
=-(-2)^2009
=2^2009