A topic of mathematical logic in Discrete Mathematics There is a light bulb and three switches a, B, C in a circuit. It is known that the light is on under the following four conditions only: (1) The key of C is up, the key of a and B is down (2) The key of a is up, the key of B and C is down (3) B, C key up, a key down (4) The pull keys of a and B are up and the pull keys of C are down Let f be 1, indicating that the light is on, and P, Q and R indicate that the key of a, B and C is up (a) Find the main disjunctive normal form of F (b) Constructing F (c) Constructing F

Let the top of the pull be represented by the letter ABC, and the bottom be represented by the negative. (a) (∧ b∧ C) ∨ (a∧ b∧ C) ∨ (a∧ b∧ C) (b) denote (∧ b∧ C) = P, (a∧ b∧ C) = q, (∧ a∧ b∧ C) = R, (a∧ b∧ C) = S. since p∧ q = (∧ p∧ q), P ∨ Q ∨ R ∨ s = (∧ P ∧)

In the original algorithm of real number
In the original algorithm of real number, we add a new algorithm "", as follows: when a ＞ = B, a b = the square of B; when a < B, a * b = a, then when x = 2, (1 * x) times X - (3 * x) =?

When x = 2,
Because 12, so 3 * x = 3 * 2 = 2 ^ 2 = 4,
x-（3*x）=2-4=-2
So (1 * x) * [x - (3 * x)] = 1 * (- 2) = - 2) ^ 2 = 4

In the original algorithm of real number In the original algorithm of real number, we add a new algorithm "*", as follows: when a ＞ = B, a * b = the square of B; when a < B, a * b = a, then when x = 2, (1 * x) times X - (3 * x) =?

RELATED INFORMATIONS

In the original algorithm of real number
In the original algorithm of real number, we add a new algorithm "", as follows: when a ＞ = B, a b = the square of B; when a < B, a * b = a, then when x = 2, (1 * x) times X - (3 * x) =?