4X square - 8x + 1 = 0, solve the quadratic equation of one variable

4X square - 8x + 1 = 0, solve the quadratic equation of one variable

The solution is 4x ^ 2-8x + 1 = 0
Its Δ = (- 8) ^ 2-4 * 4 * 1 = 48
So x = (8 + √ 48) / 8 or x = (8 - √ 48) / 8
That is, x = 1 + √ 3 / 2 or x = 1 - √ 3 / 2

The square of 2x - 4x + 1 = 0 is best for the complete step

The square of 2x - 4x + 1 = 0
x²-2x+1/2=0
（x²-2x+1）+1/2-1=0
（x-1）²=1/2
X-1 = ± 2 / 2 √ 2
X = 1 ± 2 √ 2

(2x-1) (the square of 4x + 2x + 1) = 26 (with process)
Please give me a reply as soon as possible

(2x-1)4x^2+4x^2-1=26
8x^3=27
x^3=27/8
x=3/2

On the quadratic equation x ^ 2-x + m-2 = 0 of X, there are two real roots x1, x2. If [3 + X1 (1-x1)] [3 + X2 (1-x2)] = 16, then M =?

x=x1
x1²-x1=2-m
3+x1(1-x1)
=3-(x1²-x1)
=3-(2-m)
=m+1
In the same way
3+X2（1-X2）=m+1
(m+1)²=16
m+1=±4
m=-5,m=3
Discriminant △ = 1-4 (m-2) ≥ 0
So m = - 5