Given (Tan α - 3) (sin α + cos α + 3) = 0, find the value of 4sin α - 2Sin α / 5cos α + 3sin α, 2 / 3sin square α + 1 / 4cos square α 4sinα-2sinα/5cosα+3sinα 2 / 3 sin square α + 1 / 4 cos square α

Given (Tan α - 3) (sin α + cos α + 3) = 0, find the value of 4sin α - 2Sin α / 5cos α + 3sin α, 2 / 3sin square α + 1 / 4cos square α 4sinα-2sinα/5cosα+3sinα 2 / 3 sin square α + 1 / 4 cos square α

(tanα-3)(sinα+cosα +3)=0
And sin α > = - 1
cosα>-1
So sin α + cos α > - 2
sinα+cosα+3>1
So in (Tan α - 3) (sin α + cos α + 3) = 0, it can only be tan α - 3 = 0
That is, Tan α = 3
sinα/cosα=3
sinα=3*cosα
It's OK to substitute in the formula of the required value. I can't see how your formula should be written. I'll add parentheses to the place where you should add parentheses later to separate the numerator and denominator
If sin α or cos α is not complete, the specific value can be obtained by using the above formula