The inverse function of F (x) = a ^ x (a > 0 and a ≠ 1), y = ^ - 1 (x), f ^ - 1 (2) + f ^ - 1 (5) = 1 Reply as soon as possible What is the concrete expression of the inverse function of a ^ x?

The inverse function of F (x) = a ^ x (a > 0 and a ≠ 1), y = ^ - 1 (x), f ^ - 1 (2) + f ^ - 1 (5) = 1 Reply as soon as possible What is the concrete expression of the inverse function of a ^ x?

f^-1(2)+f^-1(5)=ln2/lna+ln5/lna=ln10/lna=1
a=10

If the function f (x) = 2 to the power of X, then the inverse function f (1 / 8)=

Let f (x) = 1 / 8
2^x=1/8
x=-3
So f (- 3) = 1 / 8
So the inverse function f (1 / 8) = - 3

Let F-1 (x) be the inverse function of the function f (x) = 12 (2x − 2 − x), then the value range of X with F-1 (x) > 1 is ()
A. （34，+∞）B. （−∞，34）C. （34，2）D. [2，+∞）

Let y = 12 (2x-2-x) and 22x-2y2x-1 = 0. The solution is: 2x = y ± Y2 + 1 ∵ 2x > 0, ∵ 2x = y + Y2 + 1, ∵ x = log2 (y + Y2 + 1) ∵ F-1 (x) = log2 (x + x2 + 1). By making F-1 (x) > 1, log2 (x + x2 + 1) > 1 ∵ 2 > 1, ∵ x + x2 + 1 > 2, the solution is: x > 34, so choose a

If the inverse function of the x power of F (x) = 2 is the negative power of F (x), and the negative one of F (a) + the negative one of F (b) = 4, find the minimum value of 1 / A + 1 / b

f^-1（x）=log2^x
The negative one of F (a) + the negative one of F (b) = 4 is log2 ^ A + log2 ^ B = 4
ab=16
1 / A + 1 / B is 1 / A + 1 / b ≥ 2 √ 1 / AB = 1 / 2
The smallest 1 / 2 of a + B