If the quadratic function y = x2 + MX + (M + 3) has two different zeros, then the value range of M is () A. (-2,6)B. [-2,6]C. {-2,6}D. (-∞,-2)∪(6,+∞)

If the quadratic function y = x2 + MX + (M + 3) has two different zeros, then the value range of M is () A. (-2,6)B. [-2,6]C. {-2,6}D. (-∞,-2)∪(6,+∞)


∵ the quadratic function y = x2 + MX + (M + 3) has two different zeros, namely M2-4 (M + 3) > 0. The solution is m ∈ (- ∞, - 2) ∪ (6, + ∞), so D is chosen