As shown in the figure, in the isosceles trapezoid ABCD, ad is parallel to BC, angle B = 45 degrees, AE is perpendicular to BC, and point E, AE = ad = 2cm

As shown in the figure, in the isosceles trapezoid ABCD, ad is parallel to BC, angle B = 45 degrees, AE is perpendicular to BC, and point E, AE = ad = 2cm

If you're right, it should be 4cm

As shown in the figure, in trapezoidal ABCD, ad ‖ BC (BC > AD), ∠ d = 90 °, BC = CD = 12, ∠ Abe = 45 °, if AE = 10, the length of CE is______ ．

Through B, make the vertical line of Da intersect with the extension line of DA at m, M is the vertical foot, extend DM to g, make mg = CE, connect BG, it is easy to know that the quadrilateral BCDM is square, so BC = BM, ∠ C = ∠ BMG = 90 °, EC = GM, ≌ BEC ≌ BMG (SAS), ≌ MBG = ∠ CBE, ≌ Abe = 45 °, ≌ CBE + ∠ ABM = 45 °, ≌ GBM + ∠ ABM = 45 °, ≌ Abe = ∠ ABG = 45 °, Ag = AE = 10, set CE = X Then, am = 10-x, ad = 12 - (10-x) = 2 + X, de = 12-x, in RT △ ade, AE2 = ad2 + de2, ｜ 100 = (x + 2) 2 + (12-x) 2, that is, x2-10x + 24 = 0; the solution is: X1 = 4, X2 = 6, so the length of CE is 4 or 6

As shown in the figure, in ladder ABCD, ad ∥ BC, AC = 17, BD = 10, high AE = 8, find the length of median line of ladder
I'm sorry, but I can't make a picture yet

If the parallels of AC passing through point d intersect the extension of BC at point F, then the quadrilateral acfd is a parallelogram, AC = DF = 17, ad = CF, the perpendicular of BF passing through point D, and the perpendicular foot is point h, then DH = AE = 8. In the right angle △ BDH, the Pythagorean theorem shows that BH = 6, FH = 15, BF = 6 + 15 = 21 = BC + CF = BC + ad = 2-bit line, trapezoid ab

It is known that in trapezoidal ABCD, the median line length of the intersection line BC of ad ∥ BC, ab = 13, CD = 15, AE ⊥ BC is calculated at EAE = 12, ad = 16,
If ad = 14, other conditions remain unchanged, find the median line length of ladder ABCD
There are four answers to the second question

First find be = 5, through d make DF perpendicular to BC and F, Pythagorean theorem find CF = 9, bottom is 5 + 16 + 9 = 30, median line length is 23
Change the upper and lower letters, the same way, the upper end is 16-5-9 = 2, the median line length is 9
Ad = 14 is the same, the bottom is 5 + 14 + 9 = 28, the median line length is 21
Changing letters is a rectangle, there is no solution