Let a point a (2, - 3), B (- 3, - 2), a straight line L pass through point P (1,1) and intersect with line AB, then the value range of slope k of L is () A. K ≥ 34 or K ≤ - 4B. 34 ≤ K ≤ 4C. - 4 ≤ K ≤ 34d. K ≥ 4 or K ≤ - 34

Let a point a (2, - 3), B (- 3, - 2), a straight line L pass through point P (1,1) and intersect with line AB, then the value range of slope k of L is () A. K ≥ 34 or K ≤ - 4B. 34 ≤ K ≤ 4C. - 4 ≤ K ≤ 34d. K ≥ 4 or K ≤ - 34

As shown in the figure: according to the meaning of the question, the slope k of the straight line L satisfies K ≥ KPB & nbsp; or K ≤ kPa, i.e. K ≥ 1 + 21 + 3 = 34, or K ≤ 1 + 31 − 2 = - 4, ｜ K ≥ 34, or K ≤ - 4, i.e. the value range of the slope of the straight line is k ≥ 34 or K ≤ - 4

It is known that two points a (2,3), B (1, - 1) and the line L passing through P (1, - 1) have a common point with the line ab. the range of the slope k of the line L and the range of the inclination angle a are obtained
A complete parsing process is required
Change B (1, - 1) to B (- 1,2)

Let the analytic expression of the line l be y = KX + B
Then - 1 = K + B, that is, B = - K - 1
Y = k x - K - 1
When x = 2, y must be greater than or equal to 3
That is 2K - K - 1 ≥ 3
k≥4
When x = - 1, y must be greater than or equal to 2 to have a common point
That is - K - K - 1 ≥ 2
k≤ -3/2
That is k ≤ - 3 / 2 or K ≥ 4