Given that the image of function y = - x + 4 intersects with y axis at point a, and the image of function y = - 3x-6 intersects with X axis at point B, then ab=____

Given that the image of function y = - x + 4 intersects with y axis at point a, and the image of function y = - 3x-6 intersects with X axis at point B, then ab=____

The coordinates of point a are (0,4)
The coordinate of point B is (- 2,0)
AB = radical [(- 2) ^ 2 + 4 ^ 2] = 2 * (radical 5)

There is a point P in the image of a linear function y = - 3x, so that the distance from the point P to the X axis is equal to 3
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If the distance from P to X axis is equal to 3, then the ordinate of P is 3 or - 3
3=-3x ,x=-1
-3=-3x.x=1
P (- 1,3) or (1, - 3)

There is a point P on the image of function y = - 3x + 2, so that the distance from the point P to the X axis is equal to 3

There is a point P satisfying the condition. When y = 3, - 3x + 2 = 3, the solution is x = - 13. When y = - 3, - 3x + 2 = - 3, the solution is x = 53, - P (- 13,3) or (53, - 3)

There is a point P in the image of function y = - 3x + 2, so that the distance of PX axis is equal to 3, which is the coordinate of P

The distance from P to X axis is the absolute value of the ordinate of point P
That is to say, the ordinate of point P is 3 or - 3
Then the abscissa can be calculated