If the two constant resistors R1 and R2 are connected to the power supply in some way, the power consumed by R1 is 9W, If the two resistors are connected to the power supply in another way, the power consumed by R1 is 16W, and the current passing through R2 is 4a. If the power supply voltage remains unchanged, what is the power supply voltage and the resistance of r1r2

If the two constant resistors R1 and R2 are connected to the power supply in some way, the power consumed by R1 is 9W, If the two resistors are connected to the power supply in another way, the power consumed by R1 is 16W, and the current passing through R2 is 4a. If the power supply voltage remains unchanged, what is the power supply voltage and the resistance of r1r2

According to the fact that R1 consumes more power after changing the connection, it can be judged that the first form is series connection of two resistors and the second form is parallel connection of two resistors
Set the supply voltage as u and list three expressions
U^2/R1=16
U/R2=4
(U/R1+R2)^2R1=9
R1=9
R2=3

If the two fixed value resistors R1 and R2 are connected in one form and connected into the circuit, the electric power consumed by the resistor R1 is 9 watts; if the two resistors are connected in another form in the circuit, the power consumed by R1 is 4 watts, and R2 is known to be 50 ohm, what is u equal to

There are only series connection and parallel connection between the two resistors, in which the power of R1 is greater in parallel connection, so the power of R1 is 9W in parallel connection and 4W in series connection
Let R1 resistance value be r and power supply voltage be u
The equations can be obtained
U^2/R = 9
(U/(R+50))*(U*R/(R+50))=4
The solution is u = 30V