If the area between the two rectangles is 1400 square centimeters, calculate the perimeter of the small rectangle
What is corresponding edge
Let the length of a small rectangle be x and the width be y
Because the distance between the two rectangles is 5cm, the distance between the small rectangle and the large rectangle is 5cm
So the length of the big rectangle is x + 10cm, and the width is y + 10cm
The area between the two rectangles is equal to the area of the large rectangle minus the area of the small rectangle
That is: (x + 10) × (y + 10) - xy = 10x + 10Y + 100 = 1400
That is: x + y = 13
The perimeter of the small rectangle is 2 (x + y) = 13 × 2 = 26cm
When the length and width of a rectangle increase by 5 cm, its area increases by 125 square cm?
Let the length of the original rectangle be x cm and the width be y cm. According to the meaning of the title, the area of the increased rectangle - the area of the original rectangle = 125 square cm. The equation is as follows: & nbsp; & nbsp; & nbsp; & nbsp; (x + 5) × (y + 5) - xy = 125 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; XY + 5x + 5Y + 25-xy = 125 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 5x + 5Y + 25 = 125 & nbsp; && nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 5x + 5Y = 100 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; X + y = 20 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; because the perimeter of the rectangle = (length + width) × 2, the original perimeter of the rectangle is 20 × 2 = 40 (CM) & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; A: the circumference of the original rectangle is 40 cm