Urgent! As shown in the figure, in △ abd and △ ace, F and G are the intersection points of AC and DB, AB and EC respectively. There are four propositions: ① AB = AC; ② ad = AE; ③ AF= As shown in the figure, in △ abd and △ ace, F and G are the intersection points of AC and DB, AB and EC respectively. There are four propositions as follows: ① AB = AC. ② ad = AE, ③ AF = AG, ④ ad ⊥ BD, AE ⊥ CE. Take three propositions as the topic and the other as the conclusion to construct a proposition. Write as much as you can. Add proof. Hurry. 5 minutes

Urgent! As shown in the figure, in △ abd and △ ace, F and G are the intersection points of AC and DB, AB and EC respectively. There are four propositions: ① AB = AC; ② ad = AE; ③ AF= As shown in the figure, in △ abd and △ ace, F and G are the intersection points of AC and DB, AB and EC respectively. There are four propositions as follows: ① AB = AC. ② ad = AE, ③ AF = AG, ④ ad ⊥ BD, AE ⊥ CE. Take three propositions as the topic and the other as the conclusion to construct a proposition. Write as much as you can. Add proof. Hurry. 5 minutes

-- graph analysis: the constructed proposition is AE = ad, ad vertical BD, AE vertical CE, ab = AC, proving that AF = AG, proving that because ad vertical BD, AE vertical CE, AE = ad, ab = AC, △ abd ≌ △ ACE (according to that the hypotenuse and a right edge of two right triangles are equal, then the two right triangles are congruent

As shown in the figure, points a, B, C, D are on the circle O, ab = AC, ad and BC intersect at point E, AE = ed / 2, extend DB to point F, make FB = BD / 2, connect AF, judge straight line AF

Is the line af the tangent of circle O?

As shown in the figure, ab = AC, points D and E are on AC and ab respectively, Ag ⊥ BD, AF ⊥ CE and perpendicular foot are g and f respectively, and Ag = AF

In RT △ AGB and RT △ AFC, ab = acag = AF, ab = acag = AF, ab = acag = AF, ab = acag = AF, ab = acag = AF, ab = acag ⊥ BD, AF 8869; AF ⊥ AF ⊥ BD, AF