A rectangular block of wood, 20 cm long, 15 cm wide and 8 cm high. Saw it into 4 pieces. How many square centimeters is the sum of the surface area of the four small rectangles?

This problem, there are many results. Saw the method is not the same, the final surface area of the small cuboid is also different
1. A cross saw and a vertical saw
The surface area of the four cuboids is twice that of the original cuboid
That is: the sum of the surface area of the small cuboid is 2 * (20 * 15 * 8) = 480 square centimeters
2. If you saw three times in one direction, you can also saw four cuboids, six more cross sections
If so, there are three answers
First: cut into 4 pieces along the length
The area of small cuboid is: the cross-sectional area of large cuboid + 6 * width and height
20 * 15 * 8 + 6 * (15 * 8) = 960 square centimeters
Second: along the wide cut
The area of small cuboid is: the area of large cuboid + 6 * the cross-sectional area composed of length and height
For: 1200 square centimeters
Third: along the high cut
The area of the small cuboid is: the cross-sectional area of the large cuboid + 6 * length and width
It is 2040 square centimeters

A cuboid is 8 cm in length, 6 cm in width and 5 cm in height. Saw it into two identical cuboids. What is the maximum sum of the surface areas of the two identical cuboids? What is the minimum sum of the surface areas?

Maximum: 332cm2
Minimum: 296cm2

Saw a cuboid 8 cm in length, 3 cm in width and 2 cm in height into two small cuboids with the largest increase in surface area Square centimeter, minimum increase Square centimeter

8 × 3 × 2 = 48 (square centimeter); 3 × 2 × 2 = 12 (square centimeter); answer: the surface area increases by 48 square centimeter at most and 12 square centimeter at least

A rectangular block of wood, 20 cm long, 15 cm wide and 8 cm high. Saw it into 4 pieces. How many square centimeters is the sum of the surface area of the four small rectangles?