If one side of a square is increased by 2cm and the other side by 1cm, the area of the rectangle is 14cm2 more than that of the square, then the length of the original square is______ cm．

If one side of a square is increased by 2cm and the other side by 1cm, the area of the rectangle is 14cm2 more than that of the square, then the length of the original square is______ cm．

Let the length of the original square be xcm. According to the meaning of the question, the equation can be (x + 2) (x + 1) = x2 + 14. After solving and testing, we get x = 4. Answer: the length of the original square is 4cm

If one side of a square is increased by 2cm and the other side is increased by 1cm, the area of the rectangle is twice that of the square, 11 square centimeters more than that of the square
What is the area of the original square

Let the length of the original square be x cm
2x+1x+1×2=11
3x+2=11
3x=9
x=3
The original square area is: X × x = 3 × 3 = 9
A: the original square area is 9 square centimeters

If the length of the rectangle is reduced by 2cm and the width is increased by 1cm, it will become a square. The area of the original rectangle is 22 square centimeters less than that of the new square. Calculate the length and width of the rectangle
Solving quadratic equation with one variable
As long as it is the third level of junior high school, it is not necessary to use the quadratic equation of one variable

Let the side length of the square be xcm, then the length of the rectangle is (x + 2) cm and the width is (x-1) cm
So (x + 2) (x-1) = 2x & sup2; - 22
The solution is x = 5, or x = - 4
So the rectangle is 7cm long and 4cm wide

As shown in the figure, the length of the rectangle is 4cm, and the width is 3cm. If the length and width are increased by xcm, the area will be increased by ycm2. (1) find the function expression of Y and X; (2) find out how much the side length increases, and the area will be increased by 8cm2

(1) From the meaning of the title, we can get: (4 + x) (3 + x) - 3 × 4 = y, which is reduced to: y = x2 + 7x; (2) substituting y = 8 into the analytic formula y = x2 + 7x, we can get: x2 + 7x-8 = 0, and the solution is: X1 = 1, X2 = - 8 (rounding off).. when the side length increases by 1cm, the area increases by 8cm2

The area of a rectangle is 15cm. If its length decreases by 1cm and its width increases by 1cm, then its area increases by 1cm

Let the length of a rectangle be a and the width b be B, and its area AB = 15cm ^ 2. From the problem, we can get: (A-1) (B + 1) = 15 + 1. AB + a-b-1 = 16.15 + a-b-1 = 16. A-B = 16-14. A-B = 2. A = 2 + B. (2 + b) * b = 15. B ^ 2 + 2b-15 = 0. (B + 5) (B-3) = 0. B + 5 = 0, B = - 5 (the length cannot be negative, so we can omit) B-3 = 0, B = 3, (cm). 3A = 15

The length of a rectangle is xcm and the perimeter is 30cm. If the length is reduced by 2cm and the width is increased by 1cm, then the rectangle becomes a square
The length of a rectangle is x cm and the circumference is 30 cm. If the length is reduced by 2 cm and the width is increased by 1 cm, then the rectangle becomes a square, and the equation can be obtained________

x-2=(30-2*x)/2+1

The length and width of the rectangle are 4cm and 3cm respectively. The length and width of the rectangle are increased by xcm. The functional relationship between the increased area y and X

y = (4+x)*(3+x) - 4*3
= x²+7x+12-12
= x²+7x

If the length of one side of the rectangle is xcm and the area is YCM, y is the number of culverts of X

The radius is 25 and the diameter is 50
And diameter = the diagonal length of the rectangle
One side of the rectangle is x and the area is y
Then the other side is Y / X
Then the square of X + the square of (Y / x) = the square of 50
X + Y / x = 2500
Y / x = 2500-x
Y = (2500-x) * x
Y = x * under root sign (2500-x)

If the length of one side of the rectangle is xcm and the area is YCM, y is expressed as a function of X

The premise is that the rectangle must be inscribed
The root of y = 2x [25 ^ 2 - (x / 2) ^ 2]
Square root won't be typed. Square root in brackets

If the length of one side of the rectangle is xcm and the area is ycm2, y is expressed as a function of X, and the analytic expression of this function is______ The definition field of the function must be indicated

The length of one side of the rectangle is xcm, the other side of the rectangle is 2500 − x2cm, y = X2500 − X2, because the diameter is 50cm, so 0 ＜ x ＜ 50, so the answer is y = X2500 − X2, (0 ＜ x ＜ 50)