When the length of a rectangle increases by 2 cm and the width by 5 cm, it becomes a square, and the area increases by 60 square cm. What is the area of the original rectangle? Come on, now! thank you!!!!!!!!!

When the length of a rectangle increases by 2 cm and the width by 5 cm, it becomes a square, and the area increases by 60 square cm. What is the area of the original rectangle? Come on, now! thank you!!!!!!!!!

Let s be the area of the original rectangle, X be the side length of the square
X^2=S+60
S=(X-2)(X-5)
Equivalent substitution gives x = 10
Original area: 8 * 5 = 40

If the length of a rectangle is increased by 2 cm, the width by 5 cm, and the area by 60 square cm, it is just a square. What is the area of the original rectangle?

Because it is a square after lengthening, the original length is 3 cm more than the width. Let the length be x and the width be X - 3 cm
(x+2)*(x-3+5)-x(x-3)=60
That is 7x = 56, x = 8cm
So the area of a rectangle is 8x5 = 40 square centimeters

If the length of a rectangle is increased by six centimeters or the width by five centimeters, the area of the rectangle will be increased by 60 square centimeters

Let the length be x cm and the width be y cm
（x+6)y=xy+60 → xy+6y=xy+60 → 6y=60 → y=10
(y+5)x=xy+60 → xy+5x=xy+60 → 5x=60 → x=12
10 * 12 = 120 (square centimeter)
Answer: rectangle area 120 square centimeter