The circumference of a rectangular vegetable field is 120 meters. It is known that its width is 2 / 3 of its length,

The circumference of a rectangular vegetable field is 120 meters. It is known that its width is 2 / 3 of its length,

The design length is x meters
(1+2/3)X=120÷2
X＝36
A: 36 meters long and 24 meters wide

The perimeter of a rectangular vegetable field is 264 meters, and the length is three times the width. What is the area of this vegetable field?

Let length = x, width = y
Known: x + X + y + y = 264
X=3*Y
The solution is x = 99, y = 33
Area = x * y = 3267

The perimeter of a rectangle is 136CM. If the length is subtracted by two fifths and the width is increased by four fifths, the perimeter remains unchanged?

The sum of length and width of rectangle is 136 △ 2 = 68 cm;
If the length is x cm, the width is 68-x cm
The length is reduced by 2 / 5 to (1-2 / 5) x cm,
Width increased by 4 / 7 to (1 + 4 / 7) (68-x) cm,
The circumference remains unchanged, that is, the length and width remain unchanged,
Countable equation: (1-2 / 5) x + (1 + 4 / 7) (68-x) = 68,
The solution is x = 40, and 68-x = 28,
It is 40 cm long and 28 cm wide,
Therefore, the original rectangular area is 40 × 28 = 1120 square centimeters

Draw a line in the trapezoid below, divide the trapezoid area into two parts equally, and draw three different division methods

Because the sum of the upper and lower bottoms is 4 + 6 = 10, as long as the sum of the upper and lower bottoms is 5, the area of the trapezoid can be divided into two parts

As shown in the figure, the side length of square ABCD is 4cm, AE = 2be

According to the meaning of the question, AE = 2be, ab = ad, then AE: ab = AE: ad = AE: (AE + be) = 2:3, so the area ratio of triangle AEF and triangle ADF = EF: DF = AE: ad = 2:3; the area of triangle ADF: the area of triangle AED = 3: (2 + 3) = 3:5; the area of triangle AED is 4 × 23 × 4 △ 2 = 163 (square

The side length of square ABCD is 7 cm, and there is a triangle bef inside it (as shown in the figure). The line AE = 4 cm, DF = 2 cm, then the area of triangle bef is equal to______ Square centimeter

S △ def = (7-4) × 2 △ 2 = 3 (square centimeter), s △ bed = (7-4) × 7 △ 2 = 10.5 (square centimeter), s △ BFD = 7 × 2 △ 2 = 7 (square centimeter), s △ bef = s △ bed + s △ bfd-s △ def = 10.5 + 7-3 = 14.5 (square centimeter)

In the rectangular ABCD below, e is on ad, AE is one fourth of AD, f is on DC, DF is one half of DC, and the area of triangle bef is 181cm,
How many square centimeters is the area of ABCD? It should be simple, easy to understand and accurate

This is simple
Let AB = A and BC = B in this rectangle
The area of rectangle ABCD = ab
According to the meaning of the title, s △ BAE = 1 / 2 · AE · AB = 1 / 2 · B / 4 · a = AB / 8
S△EDF=1/2·DE·DF=1/2·3b/4·a/2=3ab/16
S△BCF=1/2·BC·CF=1/2·b·a/2=ab/4
S △ bef = s rectangle abcd-s △ bae-s △ edf-s △ BCF
=ab－ab/8－3ab/16－ab/4
=7ab/16
=181 square centimeters
The area of rectangle ABCD = AB = 181 * 16 / 7 ≈ 413.7 square centimeter
181 is prime, so it can't be divisible

The area of the triangle bef is 120 square centimeters, EF is the midpoint of AC and CD respectively, the width of the rectangle is 16 centimeters, how many centimeters is the length? (have you solved 20
The way to solve the problem is different, the result should be the same.

ABCD is a rectangle, right
AC is diagonal, e is AC midpoint, f is CD midpoint
So EF = 1 / 2 BC
Then the height of triangle bef on EF is 1 / 2 CD
therefore
S△BEF=1/2*EF*h=1/8*BC*CD=120 ²
SABCD=BC*CD=960 cm²
Because sabcd = length × width
therefore
Length × 16 = 960
Length = 60 cm

A square with a side length of 6cm, e and F are the midpoint of CD and BC respectively. How to calculate the area of shadow abod?

Can be similar to the diamond solution, diagonal vertical solution are the same, abod = 1 / 2ao * BD = 1 / 2 * 6 with the number 2 * 4.5 with the number 2 = 27, I hope to help you

As shown in the figure, it is a square with side length of 6cm. E and F are the midpoint of CD and BC respectively

S Square = 6 × 6 = 36 (square centimeter), efbd = ofod = oeob = 0.5, s (OEF) s (ODE) = 0.5, because s (OEF) + s (ODE) = s (DEF) = 0.5s (CDF) = s (CEF) = 4.5 (square centimeter), s (EOF) = 13s (DEF) = 1.5 (square centimeter), s blank = s (DEF) + s (BCE) - S (EOF) - S (CEF) = 9 + 9-1.5-4.5 = 12 (square centimeter), s shadow = s (ABCD) - s blank = 36-12 = 24 (square centimeter) A: the area of the shadow is 24 square centimeters