If the length and width of a rectangle are increased by a quarter and a third respectively, how much will its area be increased?

If the length and width of a rectangle are increased by a quarter and a third respectively, how much will its area be increased?

Increase (1 + 1 / 4) × ((1 + 1 / 3) - 1 × 1
=5/4×4/3-1
=5/3-1
=2 / 3

There is a rectangle whose length is increased by 2 / 5 and width is reduced by 1 / 4. How many points has the area of the new rectangle increased?
Use arithmetic

Suppose the length of a rectangle is a and the width is B, then its area is ab
The length increases by 2 / 5, that is, (1 + 2 / 5) a = 7 / 5A
The width is reduced by 1 / 4, that is, B-1 / 4B = 3 / 4b, so now the area of the rectangle is
(7/5a)*(3/4b)=21/20ab
The area of the new rectangle is increased
[(21/20ab)-(ab)]/ab=1/20
So the area of the new rectangle has increased by one twentieth

The length of the rectangle increases by one fifth, the width increases by one fourth, and the area of the rectangle increases by several fractions

Let length a be width B
Then s = a * B
S=6/5*a*5/4*b=3/2*a*b
S=3/2*s
So it's increased by half

As shown in the figure, it is a square with side length of 6cm. E and F are the midpoint of CD and BC respectively

S Square = 6 × 6 = 36 (square centimeter), efbd = ofod = oeob = 0.5, s (OEF) s (ODE) = 0.5, because s (OEF) + s (ODE) = s (DEF) = 0.5s (CDF) = s (CEF) = 4.5 (square centimeter), s (EOF) = 13s (DEF) = 1.5 (square centimeter), s blank = s (DEF) + s (BCE) - S (EOF) - S (CEF) = 9 + 9-1.5-4.5 = 12 (square centimeter), s shadow = s (ABCD) - s blank = 36-12 = 24 (square centimeter) A: the area of the shadow is 24 square centimeters

As shown in the figure, it is a square with side length of 6cm. E and F are the midpoint of CD and BC respectively

S Square = 6 × 6 = 36 (square centimeter), efbd = ofod = oeob = 0.5, s (OEF) s (ODE) = 0.5, because s (OEF) + s (ODE) = s (DEF) = 0.5s (CDF) = s (CEF) = 4.5 (square centimeter), s (EOF) = 13s (DEF) = 1.5 (square centimeter), s blank = s (DEF) + s (BCE) - S (

The side length of square ABCD is 1cm. E and F are the midpoint of BC and CD respectively. What is the area of shadow

As shown in the figure, two identical right triangles are stacked together to find the area of the shadow part. (unit: cm)

Because the area of Figure 1 + the area of Figure 2 - the area of Figure 2 + the area of Figure 3, so: the area of Figure 3 = the area of Figure 1, figure 1 is a trapezoid, the upper bottom is 12 cm, the lower bottom is 12-3 = 9 (CM), the height of the trapezoid is 6 cm, so the shadow area of Figure 1 is: (12 + 9) × 6 △ 2 = 21 × 6 △ 2 = 126 △ 2 = 63 (square cm). Answer: the area of the shadow part is 63 square cm ．

If a square whose side length is a is transformed into a rectangle, and if the length of one side is reduced by one unit, its area is reduced by one square
What's the length of the other side?
want

Let the other side be x, then a ^ 2 = x (A-1) + 1, and the solution is x = a + 1
So the other side is a + 1

The side length of a square is one meter, and its area is () square meters. If you use decimeter as a unit, its side length is（
The side length of a square is one meter, and its area is () square meter. If you use decimeter as the unit, its side length is () decimeter. You can calculate its area is () square decimeter

Answer: 1 10 100

One square meter is used, and the side length is______ Of square as a unit of area

According to the stem analysis, we can get: the side length is 1 meter square, the area is 1 square meter