As shown in the figure, the images of inverse scale function Y1 = K1X and positive scale function y2 = k2x all pass through point a (- 1,2). If Y1 > Y2, then the value range of X is () A. - 1 ＜ x ＜ 0b. - 1 ＜ x ＜ 1C. X ＜ - 1 or 0 ＜ x ＜ 1D. - 1 ＜ x ＜ 0 or X ＞ 1

As shown in the figure, the images of inverse scale function Y1 = K1X and positive scale function y2 = k2x all pass through point a (- 1,2). If Y1 > Y2, then the value range of X is () A. - 1 ＜ x ＜ 0b. - 1 ＜ x ＜ 1C. X ＜ - 1 or 0 ＜ x ＜ 1D. - 1 ＜ x ＜ 0 or X ＞ 1

According to the intersection rule of the inverse proportion function and the positive proportion function: the coordinates of the two intersection points are symmetrical about the origin, the coordinates of the other intersection point can be obtained as (1, - 2). From the image, it can be obtained that the value of the inverse proportion function is greater than the value of the positive proportion function at the right side of point a, the left side of the Y axis and the right side of the other intersection point at the same abscissa; ■ - 1 ＜ x ＜ 0 or X ＞ 1, so D

As shown in the figure, an intersection point of the image of the inverse scale function y and the positive scale function Y2 is a (2,1). If Y2 > Y1 > 0, find the value range of X

Substituting x = 2 and y = 1 into Y1 = K / X and y2 = KX respectively, we get
y2=1/2*x ,y1=2/x
Because Y2 > Y1 > 0
So 1 / 2 * x ＞ 2 / x, x1 ＞ - 2, X2 ＞ 2
Because Y2 > Y1 > 0, then x > 0
So x > 2