The area of the triangle formed by the line y = 3x + 6 and the two coordinate axes is () A. 6B. 12C. 3D. 24

The area of the triangle formed by the line y = 3x + 6 and the two coordinate axes is () A. 6B. 12C. 3D. 24

Let the coordinates of the intersection of the line and the x-axis be a (x, 0), and the intersection of the line and the y-axis be B (0, y). Substituting a and B into the analytical formula, we can get x = - 2, y = 6. Therefore, the coordinates of a and B are a (- 2, 0), B (0, 6). So s △ ABC = 12 × 2 × 6 = 6

Given that the area of the triangle formed by the line y = 3x + m and the coordinate axis is 6, find the value of M
emergency

When x = 0, the intercept of y-axis is m, when y = 0, the intercept of x-axis is m / - 3; then s = 1 / 2 * m * (M / | - 3 |) = 6, M = 6

If the area of the triangle formed by the line y = 3x + B and the two coordinate axes is 6 units, what is the value of B?
RT

The intersection of line and X axis is: 0 = 3x + B, x = - B / 3
The intersection point with y axis is y = 3 * 0 + B, y = B
When b > 0, s = 1 / 2 * b * | - B / 3|
6 =b^2/6
b^2=36 b=6
When B

What is the area of the triangle formed by the line y = 3x-2 and the coordinate axis?

Let x = 0
y=-2
Let y = 0
x=2/3
Triangle area = 1 / 2 * 2 * 2 / 3 = 2 / 3