In the plane rectangular coordinate system, given a (x, y), and xy = - 2, try to write two points that satisfy the condition

In the plane rectangular coordinate system, given a (x, y), and xy = - 2, try to write two points that satisfy the condition

(- 1,2), (- 2,1) ah, isn't it very simple

In the plane rectangular coordinate system xoy, the position of the quadrilateral ABCD is shown in the figure, a (0,4), B (- 2,0), C (0, - 1), D (3,0), the moving point P (x, y) is in the first quadrant, and satisfies s △ pad = s △ PBC. Find the relationship between the abscissa and ordinate of point P (use X to represent y), and write out the value range of X

The equation of straight line ad is: 4x + 3y-12 = 0, and | ad | = 5 the equation of straight line BC is: x + 2Y + 2 = 0, and | BC | BC | = 5 the equation of straight line BC is: x + 2Y + 2 = 0, and | BC | BC | BC | BC | BC | BC | BC | BC | BC | = 5 set P point coordinates (x, y, (x, y, y), (x | 0, y | 0, y | 5pthe distance from straight line ad to straight line ad is the distance of the distance of P to straight line ad ad, and the distance of straight line ad = | 4x | 4x + 4x + 4x + 4x + 3x + 3x + 3Y − 12 | 5 = 12 · 5 | x + 2Y + 2 | 5 When y = 14-3x, 0 < x < 143, when y = 2-x, 0 < x < 2

In the plane rectangular coordinate system xoy, if the part of the curve y = ax (a > 0 and a ≠ 1) in the second quadrant is in the plane region represented by the inequality (x + Y-1) (X-Y + 1) > 0, then the value range of a is ()
A. 0＜a≤1eB. 1e≤a＜1C. 1＜a≤eD. a≥e

Draw the plane region represented by the inequality (x + Y-1) (X-Y + 1) > 0, the curve y = ax (a > 0 and a ≠ 1) in the second quadrant is in the plane region represented by the inequality (x + Y-1) (X-Y + 1) > 0, a > 1, the line X-Y + 1 = 0 is tangent to the curve y = ax, and the point (0, 1) is the zero boundary position, and (AX) ′ = axlna, then LNA = 1, that is, a = e  1 < a ≤ e, so choose C

Point P moves on the curve y = x3-x + 2. If the inclination angle of the tangent at point P is α, then the value range of angle α is ()
A. [0，π2)∪(π2，3π4]B. (π2，3π4]C. [3π4，π)D. [0，π2)∪[3π4，π)

∵ point P moves on the curve y = x3-x + 2. Let the inclination angle of the tangent at point p be α, ∵ y ′ = 3x2-1 ≥ - 1, ∵ k = Tan α≥ - 1. According to the image of tangent function: ∵ inclination angle is α ∈ [0, π) ∵ 3 π 4 ≤ α < π or 0 ≤ α < π 2, so D