After the parabola y = - X2 is shifted 2 units to the left, the analytical expression of the parabola is () A. y=-（x+2）2B. y=-x2+2C. y=-（x-2）2D. y=-x2-2

After the parabola y = - X2 is shifted 2 units to the left, the analytical expression of the parabola is () A. y=-（x+2）2B. y=-x2+2C. y=-（x-2）2D. y=-x2-2

∵ the vertex of the original parabola is (0,0), ∵ the vertex of the new parabola is (- 2,0), let the analytic formula of the new parabola be y = - (X-H) 2 + K, ∵ the analytic formula of the new parabola is y = - (x + 2) 2, so a

If a parabola is translated down and to the right by 2 units, the parabola obtained is y = - X2, then the analytical expression of the parabola is ()
A. y=-（x-2）2+2B. y=-（x+2）2-2C. y=-（x+2）2+2D. y=-（x-2）2-2

The vertex of the new parabola is (0, 0), and it is translated 2 units up and 2 units to the left to obtain the analytic formula of the original parabola. Then the vertex of the original parabola is (- 2, 2). Let the analytic formula of the original parabola be y = - (X-H) 2 + K, and substitute it with y = - (x + 2) 2 + 2. So select C

The straight line x = 2 of the symmetry axis of the parabola y = (k2-2) x2-4kx + m, and its lowest point is on the straight line y = - 1 / 2 + 2, find the analytic expression of the function

If x = 2 is brought into y = - 1 / 2x + 2, the lowest point (vertex) of y = 1 is (2,1). According to vertex formula (- B / 2a, 4ac-b2 / 4A), K1 = - 2, K2 = 1 ∵ analytic expression has lowest point, so k2-2 > 0, so k = - 2 ∵ y = 2x & # 178; + 8x + m brings point (2,1) into M = - 23, so analytic expression is y = 2x & # 178; + 8x-23