If the vertex of parabola y = x & # 178; + 4 is p, and the two intersections of parabola y and X are C and D, then the area of triangle PCD is_________

If the vertex of parabola y = x & # 178; + 4 is p, and the two intersections of parabola y and X are C and D, then the area of triangle PCD is_________

There is no intersection between + 4 and X axis
I think the title might be y = x & # 178; + 4x
Then y = x & # 178; + 4x = (x + 2) &# 178; - 4
Vertex P (- 2,4)
x²+4x = 0
x(x+4) = 0
x₁ = 0,x₂ = - 4
Intersection with X axis (0,0) (- 4,0)
∴S(△PCD) = 1/2 × 4 × 4 = 8

If the vertex of the parabola y = - x2 + 8x-12 is p, and the two intersections with the X axis are C and D, then the area of △ PCD is______ ．

Because the vertex of the parabola y = AX2 + BX + C (- B2A, 4ac − b24a), the vertex of the parabola y = - x2 + 8x-12 is p (4, 4). When y = 0, - x2 + 8x-12 = 0, the solution is x = 2 or x = 6, so the coordinates of the two intersections C and D with the X axis are (2, 0), (6, 0). So the area of △ PCD is 8