Given the function y = y1-y2, and Y1 is inversely proportional to x + 1, Y2 is positively proportional to X2, and x = - 2 and x = 1, the value of Y is 1. Find the functional relation of Y with respect to X

Given the function y = y1-y2, and Y1 is inversely proportional to x + 1, Y2 is positively proportional to X2, and x = - 2 and x = 1, the value of Y is 1. Find the functional relation of Y with respect to X

When x = - 2, y = 1; when x = 1, y = 1; when x = 4k1 + K2 = 1k1 − K22 = 1, the solution is: K1 = 12k2 = − 1; y = 12x2 + 1x + 1

Given the function y = Y1 + Y2, Y1 is proportional to x, Y2 is proportional to x + 3
When x = - 1 is y = - 7. When x = 5, y = - 19, find the analytic expression of the function

y1 = k1x ,y2 = k2(x + 3)
y
= y1 + y2
= k1x + k2(x + 3)
Substituting x = - 1, y = - 7 and x = 5, y = - 19, we get the following result:
-k1 + 2k2 = -7
5k1 + 8k2 = -19
The solution is as follows
k1 = 1
k2 = -3
So y = - 2x - 9

Given the function y = y1-y2, where Y1 is proportional to X-1, Y2 is proportional to 2x + 3, and when x = 1, y = - 1; when x = 3, y = 2, find the analytic expression of the function of Y and X
200 - 14 days and 23 hours to the end of the problem
Given the function y = y1-y2, where Y1 is proportional to X-1, Y2 is proportional to 2x + 3, and when x = 1, y = - 1; when x = 3, y = 2, find the analytic expression of the function of Y and X

Let Y1 = K1 (x-1), y2 = K2 (2x + 3)
-1=0*k1-5*k2
2 = 2 * k1-9 * K2, K1 = 1.9, K2 = 0.2
Y=1.5x-2.5

Given the line Y1 = x, y2 = 1 / 3x + 1, no matter what value x takes, y always takes the maximum value of Y1, Y2, find the expression of function y and its minimum value (process)

Let Y1 = Y2, then x = 1 / 3x + 1, and the solution is x = 1.5
When XY2, y takes Y1
y={1/3x+1 （x=1.5）
Y has no minimum because y increases monotonically

As shown in the figure, there is a parabolic arch bridge with a maximum height of 16m and a span of 40m. Now put its schematic diagram in the plane rectangular coordinate system, and the functional relationship of the parabola is______ ．

According to the meaning of the problem, the vertex of the analytic expression of the function is (20,16), ∧ let the analytic expression be y = a (x-20) 2 + 16, ∧ the function image passes through the origin (0,0), ∧ 0 = 400A + 16, ∧ a = - 125, ∧ y = - 125 (x-20) 2 + 16

In the plane rectangular coordinate system, if P (1, - 1) is known, the tangent of parabola y = x ^ 2 is made through P, and the tangent point is m (x1, Y1) n (X2, Y2) (where X1 is less than x2), the values of X1 and X2 are calculated

The tangent slope of any point (x0, Y0) passing through the parabola y = x ^ 2 is 2x0, so the tangent equation passing through any point (x0, Y0) is (point oblique): y = 2x0 (x-x0) + x0 ^ 2, that is, y = 2x0 X - x0 ^ 2. Now, it is required that the tangent passes through P (1, - 1), that is, the coordinates of P should meet the tangent equation

Given that the three points a (- 2, Y1), B (- 1, Y2) and C (3, Y3) are on the image of parabola y = 2x ^ 2-3, then the values of Y1, Y2 and Y3 are large

According to the meaning of the title:
y1 = 2*(-2)²-3 = 5 ,
y2 = 2*(-1)²-3 = -1 ,
y3 = 2*3²-3 = 15 ,
So, Y2 < Y1 < Y3

What is the number of intersections between the straight line y = 2x + m and the parabola y = - x2 + 3x + 4?

Substituting the straight line y = 2x + m into the parabola y = - x2 + 3x + 4, we get
2x+m=-x^2+3x+4 => x^2-x+m-4=0
△=1-4(m-4)=17-4m
If M > 17 / 4, then △ 17 / 4, then △ 0, the equation has two different solutions and two intersections

The coordinates of the intersection of the line y = 3x + 4 and the parabola y = x2 are

3x+4=x2
The solution of the equation is: x = 4 or x = - 1
When x = 4, y = 16, when x = - 1, y = 1
The intersection coordinates are (4,16) (- 1,1)

Find the intersection coordinates of the straight line y = 2x + 2 and the parabola y = 1 / 2x2 + 3x + 5 / 2

Simultaneous equations:
2x+2=x^2/2+3x+5/2
x^2+2x+1=0
(x+1)^2=0
x=-1
y=-1*2+2=0
That is, the coordinates of the intersection point are (- 1,0)