The probability of a and B is equal to the probability of a plus the probability of B is equal to 1. What events are a and B

The probability of a and B is equal to the probability of a plus the probability of B is equal to 1. What events are a and B

Provide you with accurate answers
P(A∪B)=P(A)+P(B)-P(AB)=P(A)+P(B)=1
It shows that P (AB) = 0 and P (a) + P (b) = 1
Then a and B are opposite events
Learning dictionary team answers for you

Let the probability density of two-dimensional random variable (x, y) be f (x, y) = {a (x + y), 0 small equal to X Small equal to 2, 0 small equal to y small equal to 20, others}
1, find a 2, P {x is less than 1, y is less than 1} 3, P {x + y is less than 3}

∫ (from 0 to 2) ∫ (from 0 to 2) a (x + y) DXDY = ∫ (from 0 to 2) [ax ^ 2 / 2 + ax] (x from 0 to 2) dy = ∫ (from 0 to 2) (2a + 2ay) dy = (2ay + ay ^ 2) (from 0 to 2) = 4A + 4a-0-0 = 8A = 1, so a = 1 / 8
∫ (from 0 to 1) ∫ (from 0 to 1) (1 / 8) (x + y) DXDY = ∫ (from 0 to 1) ((1 / 16) x ^ 2 + (1 / 8) XY) (x from 0 to 1) dy = ∫ (from 0 to 1) ((1 / 16) + (1 / 8) y) dy = [(1 / 16) y + (1 / 16) y ^ 2] (from 0 to 1) = 1 / 16 + 1 / 16-0-0 = 1 / 8, so the probability is 1 / 8
As a result, the ∫ (from 0 to 2) (from 0 to 0 to 3-y) (from 0 to 3-y) (from 0 to 3-y) (1 / 8) (x + y) DXDY = (from 0 to 2) (from 0 to 2) (1 / 16) x ^ 2 + (1 / 8) XY (1 / 16) x (1 / 16) x ^ 2 + (1 / 8) XY (1 / 8) (1 / 16) (1 / 16) (3-y) (from 0 to 2) (from 0 to 2) (from 0 to 2) (from 0 to 2) (from 0 to 2) (from 0 to 2) (from 0 to 2) [(9 / 16) [(9 / 16) - - (3 / 16) - - (3 / 8) as (9 / 16) - - (3 / 8) (3 / 8) (3 / 8) (3 / 8) (3 / 8) as as as as (9 / 16) - - (3 / 8) y - (3 / 8) y - (3 / 8) (3 / 8) y - (3 / 8) as as as as as as as as 16)] dy = [(9y / 16) - (y ^ 3 / 48)] (from 0 to 2) = 9 / 8-1 / 6 = 23 / 24, so the probability is 23 / 24

If two numbers are randomly taken out in the interval (0,1), the probability that the sum of the two numbers is less than 5 / 6 is zero
Add them up to 0 to 2, and then the probability of less than 5 / 6 is 5 / 12. Why not

No, we should understand it with the help of coordinate system
If x and Y belong to (0,1), the area they form is the interior of a square, and the four vertices are (0,0) (0,1) (1,0) (1,1), and their area is 1,
In the region of X + y < 5 / 6, the area is the triangle area with (0,0) (0,5 / 6) (5 / 6,0) as the vertex, which is equal to 25 / 72
So if two numbers are randomly taken out in the interval (0,1), the probability that the sum of the two numbers is less than 5 / 6 is (25 / 72) / 1 = 25 / 72

If two numbers are randomly selected in the interval (0,1), the probability that the sum of the two numbers is less than 6 / 5 is zero
Using the best value to solve problems
Minimum = 0
Maximum = 2
Probability = (6 / 5) / 2 = 3 / 5
Why is the above solution wrong?
Why can't we get it by dividing the length? Can we be more specific? I see. 20 more points

The two numbers taken can be set as (x, y), then (x, y) obeys 0

If any two numbers are selected in the interval (0,1), the probability that the sum of the two numbers is less than 5 / 6 is?
25 / 72 is not right. It's addition, not multiplication. The answer is A12 / 25 B18 / 25 C16 / 25 d17 / 25

If any two numbers in the interval (0,1) are x, y, then 0 & lt; X & lt; 1,0 & lt; Y & lt; 1, so that the sum of these two numbers is less than 5 / 6, x, y satisfies x + Y & lt; 5 / 6, the area of the shadow part of the drawing is 1 / 2 × (5 / 6) × (5 / 6) = 25 / 72, and the area of the square is 1

In the interval [0, TT), randomly take a number x, the probability that the value of SiNx is between 3 and 1

In the interval [0, π], X satisfying √ 3 / 2 ≤ SiNx ≤ 1 is π / 3 ≤ x ≤ 2 π / 3
According to the geometric probability formula, the probability is (2 π / 3 - π / 3) / π = 1 / 3

The probability that the absolute value of the difference between two numbers is less than 1 if two numbers are randomly selected from the interval (0 2)

Area ratio: please see the picture:

The probability of taking a random number x in the interval [- 3,3] such that | x + 1 | - | X-2 | ≥ 1 holds^_ ^The idea is very clear. I don't know how to get the correct interval in the calculation process,

First calculate the interval of the inequality, then calculate the length divided by the total length

Take a random number in the interval [- 2,3], then the probability of | x | ≤ 1 is
I'm - 2 - 10 1 2 3, and I get - 1,0,1, so p = 0.5, but the answer is 2 / 5

|x|

If we take a random number x on the interval [- 1,2], then | X|

|x|