[2/xy/(1/x+1/y)2+(x2+y2)/(x2+2xy+y2)]*2x/(x-y)

[2/xy/(1/x+1/y)2+(x2+y2)/(x2+2xy+y2)]*2x/(x-y)

[2/xy/(1/x+1/y)²+(x²+y²)/(x²+2xy+y²)]*2x/(x-y)
=[2/xy/(x+y)²/x²y²+(x²+y²)/(x+y)²]*2x/(x-y)
=[2xy/(x+y)²+(x²+y²)/(x+y)²]*2x/(x-y)
=[(2xy+x²+y²)/(x+y)²]*2x/(x-y)
=(x+y)²/(x+y)²*2x/(x-y)
=2x/(x-y)

Given that X and y are positive numbers, and x > y, the proof is: 2x + 1 / (x2-2xy + Y2) > = 2Y + 3

Let x = y + Z (z > 0)
Then the original formula = 2 (y + Z) + 1 / (Z ^ 2) = 2Y + 2Z + 1 / (Z ^ 2) = 2Y + Z + Z + 1 / (Z ^ 2)
(Z + Z + 1 / (Z ^ 2)) / 3 "1 (mean of three terms)
So the original formula = 2Y + Z + Z + 1 / (Z ^ 2) 2Y + 3

Given that the n-th power of - 3 / 2XY is the same as the m-th power Y2 of 6x, what is M-N equal to?

If two formulas are of the same kind, then the powers of X and y are equal, that is, M = 1, n = 2
So M-N = 1-2 = - 1

If the N + 1 power of 5x and the 3 power of * y + 2xy-3 is a six degree trinomial, then the value of n is equal to ()

According to the meaning of the title
n+1+3=6
n=2