In RT triangle ABC, angle c = 90 degrees, G is the center of gravity, ab = 12, CG =?

In RT triangle ABC, angle c = 90 degrees, G is the center of gravity, ab = 12, CG =?

The median length is 6
CG=2/3*6=4

In △ ABC, ad = 1 / 2Ab, be = 2 / 3bC, if de = in 1ab + in 2Ac, then in 1 + in 2

Are all vectors
Ad = AB / 2, that is: BD = Da = BA / 2 = - AB / 2
BE=2BC/3=2(AC-AB)/3
So: de = be-bd = 2 (ac-ab) / 3 + AB / 2
=2AC/3-AB/6=-AB/6+2AC/3
That is: λ 1 = - 1 / 6, λ 2 = 2 / 3
That is: λ 1 + λ 2 = 1 / 2

In the triangle ABC, if the vector BC = λ 1ab + λ 2Ac, then λ 1, λ 2=

BC=AC-AB=-AB+AC
So: λ 1 = - 1, λ 2 = 1
That is: λ 1, λ 2 = - 1