If the two right sides of a right triangle are 5, 12, what is the radius of the inscribed circle of a right triangle

If the two right sides of a right triangle are 5, 12, what is the radius of the inscribed circle of a right triangle

two

Given that the radius of the circumscribed circle of an isosceles right triangle is 5, the radius of the inscribed circle is ()
A. 52+5B. 122-5C. 52-5D. 102-10

∵ the radius of circumcircle of isosceles right triangle is 5, the length of hypotenuse of this right triangle is 10, the two right sides are 52, and the radius of inscribed circle is r = 12 (52 + 52-10) = 52-5, so C

If the radii of circumscribed circle and inscribed circle of a right triangle are 5 and 2 respectively, the right triangle
Then the sine value of the smaller acute angle in the right triangle is

Let the length of side be a, B, C respectively, where C is the hypotenuse
From the circumcircle radius of right triangle is 5, C = 2 * 5 = 10
5 (a + B-C) = 2
a+b=14
And because the square of a + the square of B = the square of 10
The equations are solved simultaneously, and the lengths of the three sides are 6, 8 and 10, respectively

If the radius of the circumscribed circle of an isosceles right triangle is 1, then the radius of its inscribed circle?

Root 2 minus 1