As shown in the figure, the triangle ABC is an equilateral triangle, and D is the midpoint on the side ab. it is known that the area of the triangle BDE is 5 square centimeters. Find the area of the equilateral triangle ABC

Connect AE, cross the opposite side of a, make a vertical AF, cross BC and F, then s △ BDE = s △ ade = 5 (square centimeter) s △ Abe = s △ BDE + s △ ade = 10 (square centimeter) because D is the midpoint of AB side, de ⊥ BC, so be = EF, s △ Abe = s △ AEFs △ ABF = s △ Abe + s △ AEF = 10 + 10 = 20 (square centimeter) 2S △ ABF = s △ ABCs △ ABC = 2 × 20 = 40 (square centimeter) answer: the area of triangle ABC is 40 square centimeter

As shown in the figure, triangle ABC is an equilateral triangle, D is the midpoint of AB, De is perpendicular to BC, CE = 3bE, the area of triangle BDE is 6m2, find the area of triangle ABC

Connect CD, because CE = 3bE, so BC = 4be, then the area of triangle BDC = the area of triangle BDE × 4, and because D is the midpoint of AB, so the area of triangle ABC = the area of triangle BCD × 2. Then the area of triangle ABC = the area of triangle BDE × 4 × 2 = 6 × 4 × 2 = 48 (square meters). A: the area of triangle ABC is 48 square meters

As shown in the figure, the triangle ABC is an equilateral triangle, and D is the midpoint on the side ab. it is known that the area of the triangle BDE is 5 square centimeters. Find the area of the equilateral triangle ABC

Known: C is the midpoint of line AB, D is the point on CB, e is the midpoint of DB, if CE = 4, find the length of line ab. known: as shown in the figure, C is the midpoint of line ab
Point, m and N are the midpoint of line AC and BC, ab = 11, Mn

NM=1/2 AB=11/2=5.5

Given that the line segment AB = 4.8cm, C is the midpoint of AB, D is the midpoint of CB, point E is on AB, and CE = 1 / 3aC, draw a graph and calculate the length of de
What I asked is that the whole process should be written, because it's better to give it to how to draw a picture and add points quickly

Because C is the midpoint of AB, then AC = 2.4cm;
Because D is the midpoint of CB, CD = 1.2cm;
CE=1/3AC=0.8cm
If e is between AC, de = CE + CD = 2cm;
If e is between CD, de = cd-ce = 0.4cm

Given that there are two points c and D on the line AB, and AC: CB = 4:3, ad: DB = 2:5, if CD = 4cm, find the length of the line ab
The sooner the better, the greater the reward

Let AB = 7x
∵AC：CB＝4：3,AB＝7X
∴AC＝4X,CB＝3X
∵AD：DB＝2：5
∴AD＝2X,DB＝5X
∴CD＝AC-AD＝4X-2X＝2X
∵CD＝4
∴2X＝4
X＝2
∴AB＝7X＝14（cm）

The points c and D are on the line AB, and the lengths of the segments AC, CB, ad and DB are AC: CB = 5:4, ad: DB = 2:1, and CD = 2cm, so the length of the segment AB is calculated

The points c and D are on the line AB, and the lengths of the segments AC, CB, ad and DB are AC: CB = 5:4,
Then AC = 5 / 9ab
And because ad: DB = 2:1, then ad = 2 / 3AB
AD-AD=2/3AB-5/9AB
CD = 1 / 9ab, because CD = 2cm, ab = 18cm

BC is equal to half AB, D is the midpoint of AC, DC = 2cm, find the length of ab
As long as you answer, it's urgent

∵ D is the midpoint of AC, DC = 2
∴AC=2DC=4
And ∵ BC = 1 / 2 ab
∴AC=AB+BC=AB+1/2 AB = 3/2 AB=4
∴AB=4÷3/2=8/3

Given the line segment AB, extend AB to C so that BC = half AB, extend AC to D reversely so that Da = half AC. if AB = 8 cm, calculate the length of DC
Wrong title,
If the line segment AB is known, extend AB to C so that BC = half AB, extend AC to D reversely so that Da = one third AC, then the length of line segment DC is equal to_________

D——A————B——C
∵AB＝8,BC＝1/2AB
∴BC＝4
∴AC＝AB+BC＝12
∵DA＝1/2AC
∴DA＝6
∴DC＝DA+AC＝6+12＝18（cm）
The math group answered your question,

If the line AB is known, extend AB to C so that BC = 1 / 2Ab, D is the midpoint of AC, DC = 3cm, then the length of line AB is

dc=(ab+bc)/2=3
ac=ab+bc=6
Because BC = AB / 2
So AB + BC = 3 / 2Ab = 6
The solution is ab = 4

As shown in the figure, the triangle ABC is an equilateral triangle, and D is the midpoint on the side ab. it is known that the area of the triangle BDE is 5 square centimeters. Find the area of the equilateral triangle ABC