(1) In triangle ABC, a = 2, B = 2 √ 3, B = 60 ° are known to solve triangle ABC (2) In triangle ABC, we know a = √ 3, B = √ 2, B = 45 ° to solve triangle ABC

(1) In triangle ABC, a = 2, B = 2 √ 3, B = 60 ° are known to solve triangle ABC (2) In triangle ABC, we know a = √ 3, B = √ 2, B = 45 ° to solve triangle ABC

(1) According to the sine theorem, a / Sina = B / SINB, so a = 30 degrees, that is, C = 90 degrees, so AB = 4 is not classified
(2) From the sine theorem, a / Sina = B / SINB, so a = 60 degrees or 120 degrees, C = 75 degrees or 15 degrees. By using the sine theorem again, C = (radical 6 + radical 2) / 2 or (radical 6 - radical 2) / 2 can be obtained

In the triangle ABC, we know that a = 18, B = 20 and angle a = 150 degrees

In the solution of oblique triangle, you only need to use two formulas, one is the sine theorem, the other is the cosine theorem. It is better to teach people to fish than to teach them to fish

In △ ABC, the angles a, B and C are opposite to three sides a, B and C respectively. It is known that a = 5, B = 2 and B = 120 ° to solve the triangle

Because a = 5, B = 2, B = 120 degrees, so a ＞ B = 120 degrees, so a + B ＞ 240 degrees, which is contradictory to a + B + C = 180 degrees, so this triangle has no solution