The interval of definite integral ∫ ((1-x ^ 2) ^ 3) ^ 0.5dx is 0 to 1

The interval of definite integral ∫ ((1-x ^ 2) ^ 3) ^ 0.5dx is 0 to 1


Let x = Sinz, DX = cosz, DZ
∫(0→1) (1 - x²)^(3/2) dx
= ∫(0→π/2) cos³z * (cosz dz)
= ∫(0→π/2) cos⁴z dz
= (4 - 1)!/4!* π/2
= 3!/4!* π/2
= (3 * 1)/(4 * 2 * 1) * π/2
= 3π/16



How to find the definite integral of (SiNx) ^ 3 / {(cosx) ^ 4 + (SiNx) ^ 2} from 0 to 10pi?





In [0, Wu / 2] to [SiNx (cosx) ^ 3] definite integral of the detailed steps





Finding definite integral (0, π) SiNx / 1 + (cosx) ^ 2



Elden Ring Premiere

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