G (x) and f (x) = sin (x / 2 + π / 6) are symmetric with respect to the straight line x = π

If the image of G (x) and f (x) = sin (x / 2 + π / 6) is symmetric with respect to the line x = π, then G (x) = f (2 π - x) = sin [(2 π - x) / 2 + π / 6] = sin (- X / 2 + 7 π / 6) = sin (x / 2 - π / 6), that is g (x) = sin (x / 2 - π / 6)

Ln (1-T ^ 2) DT, the upper and lower limits of the integral are x and 0 respectively. What is the result?
RT

The use of partial integration

It is known that the equation X3 + (1-A) x2-2ax + A2 = 0 has only one real root, then the value range of real number a is______ ．

The original equation is transformed into (x-a) (x2 + x-a) = 0, and x = a or x2 + x-a = 0, because the equation X3 + (1-A) x2-2ax + A2 = 0 has and only has one real root, so x = a is the only real root of the equation, so the equation x2 + x-a = 0 has no real root, so △ = 1 + 4A < 0, so a < - 14

Find the definition field of function y = root sign negative cosx + root sign Cotx
Detailed problem solving process

-cosx>=0,cotx>0
cotx=cosx/sinx,cosx=

Let a and B be out of plane lines with an included angle of 30 degrees, then the conditions are satisfied: a belongs to alpha, B belongs to beta, and how many pairs of planes are alpha perpendicular to beta?
A does not exist, B has only 2 pairs, C has only 1 pair and D has countless pairs

Let a, B be a non planar line with an angle of 30 ° and satisfy the condition "A & ⊂ α, B & ⊂ β, and α⊥ β" plane α, β () A. there is no B. There are only two pairs of C. There are only one pair of D. there are countless pairs of test points: basic properties and corollaries of plane

If plane α and line L are known, then at least one line in plane α and l ()
A. Parallel B. intersect C. perpendicular D. out of plane

If l ⊥ α, then the line will not intersect any line in the plane, so exclude B. if l ⊥ α, then the line will not be parallel to any line in the plane, so exclude A. if l ⊂ α, then the line and any line in the plane are coplanar, so exclude D. so select C

It is known that plane alpha intersects plane beta = a, B on alpha, C on beta, B intersects a on a, and C is parallel to A. using the method of disproportion to prove that B and C are different

If B and C are coplanar, then B and C intersect or are parallel. (1) if B and C are parallel, then a and B are parallel because a and C are parallel. (2) if B and C are parallel, then a and B are parallel,
C intersects. Let the intersection point be point a, because B is on alpha and C is on beta, so a is on alpha and beta, so a is on the common line a of alpha and beta, then a and C intersect and contradict

Given the plane vector alpha, beta (alpha is not equal to 0, alpha is not equal to beta), the membrane of beta is 1, and alpha is equal to beta-
If the included angle of alpha is 120 degrees, the range of alpha membrane is 0

Any point a in plane γ (not on L)
Let α ∩ γ = M
β∩γ=n
Make ab ⊥ m over a over b
Let a be AC ⊥ n over C
α⊥ γ, so m ⊥ α, l is in plane α, l ⊥ M
β⊥ γ, so n ⊥ β, l is in the plane β, l ⊥ n
m. N is in the plane γ and intersects a
So l ⊥ γ

In terms of wavelength, it is radio wave > infrared > visible > ultraviolet > X-ray > gamma ray
So, 1. Where are the wavelengths of roentgen ray, alpha ray and beta ray
What's the composition of roentgen ray?

Roentgen ray is X-ray, which is a kind of electromagnetic radiation emitted by the energy released by the innermost electron transition of atom
wave
Alpha ray is a stream of helium nuclear particles. Its velocity is about one tenth of the speed of light, not to mention the wavelength
Beta ray is a high-speed electron stream, the velocity is about 90% of the speed of light, so it is not wavelength. It is also produced by the decay of some radioactive element nuclei
Roentgen ray is a kind of electromagnetic wave. It can not be said that it is composed of electromagnetic waves, but the essence of roentgen ray is a kind of electromagnetic wave. But in some cases, it can be understood as photons, such as photoelectric effect

When k is a value, the equation x - (2k-1) x + k = 0 of X has two unequal real roots. Find the real number range of K

Because the quadratic coefficient of the equation is greater than 0
Therefore, if the equation has two unequal real roots, then
△=(2k-1)²-4k=4k²-8k+1>0——>4(k-1)²-3>0——>(k-1)²>3/4——>k(1+√3)/2

G (x) and f (x) = sin (x / 2 + π / 6) are symmetric with respect to the straight line x = π