Find all such primes: it is the sum of two primes and the difference of two primes Is there anything else besides five?

5, except for 5, there is no prime. It is not difficult to see that all prime numbers except 2 are singular. However, the sum or difference of two singular numbers must be even. Even numbers can not be prime. So we need to find only the addend and the subtracted numbers must be 2. There are only 3, 5 and 7 numbers separated by 2 and adjacent to 3 numbers

The difference between the two primes is 1, and the ratio of the two primes is 1 Their greatest common factor is The least common multiple is__ ．

In addition to the smallest prime number 2, the minimum difference between any two prime numbers is 2. Therefore, the two prime numbers whose difference is 1 have only 2 and 3. Their greatest common factor is 1 and their least common multiple is 6. So the answer is: 2:3 or 3:2, 1, 6

A two digit prime number whose difference between two numbers is 4. Such prime numbers are (), (), ()

A two digit prime number, the difference between its two numbers is 4, such prime numbers are (37), (59), (73)

If the difference between two prime numbers is 17, what is the sum of the two prime numbers?

If the difference between two prime numbers is 17, what is the sum of the two prime numbers?
Because the difference between the two prime numbers is 17 (odd),
So these two numbers must be odd and even,
Because there is only two even numbers in prime numbers,
So another prime number
It must be 2 + 17 = 19,
So the sum is 2 + 19 = 21

How much is one plus 1993.68?

1993.68+1=1994.68

There is a natural number and it wants to subtract, add, multiply, divide the four results together, just equal to 36, the natural number is ()
The calculation process and why

Let this natural number be a
a－a＋a＋a＋a·a＋a÷a＝36
a²＋2a＝35
a﹙a＋2﹚＝35＝5×7
∴ a＝5

What is the sum, difference, product and quotient of a natural number added, subtracted, multiplied and divided by itself?

Let X: 2x + 0 + XX + 1 = 1999
2x+xx=1999-1
Sorry, I can't solve the rest. You can ask the teacher. I'm really sorry

If a natural number is added, subtracted, multiplied, and divided by itself, the sum of sum, difference, product, and quotient is 4762, what is the number

Let this number be a [natural number] summation: 2A subtraction: 0 phase product: A & # 178; division quotient: 12a + 0 + A & # 178; + 1 = 4762 (a + 1) & # 178; = 4762 a + 1 = ± 69.007245996344470839965393681702 a = 68.007245996344470839965393681702 a = - 70.0072

The difference, sum, quotient and product of a natural number and its own subtraction, addition, division and multiplication add up to 81. What is the natural number? Solve it

Let this natural number be X
So the natural number subtracts itself to zero
Add up to 2x
Divide by 1
Multiplication is the square of X
So it adds up to 81
2x+1+x*x=81
x*x+2x-80=0
The solution is x = - 10
Or x = 8
Because it's a natural number, it's 8
I don't know how to ask

1. There are three natural numbers. They all get the same result when they are added or multiplied. The largest of the three natural numbers is__ .
2.2,4,6,8,..., 98100, the sum of the 50 even numbers is .
3. There are several hats in a box. They are red except two, blue except two, and yellow except two. There are three hats in the box A hat
Is 4.359999 prime or composite?
5. If the sum of 1999 consecutive natural numbers is exactly a complete square number, then the minimum value of the largest one of the 1999 consecutive natural numbers is .
Xiaohong needs to be dirty three times. In order not to produce less than 10 yuan redemption each time, she should bring at least 5 yuan, 2 yuan and 1 yuan coins_ There are only five, two and one coins

2.2+4+…… +100=2×(1+2+…… +50)=2×50×51/2=2550；
3. Except the two tops, they are all red, and there are blue and yellow in the box, so there is one blue and one yellow; except the two tops, they are all blue, and there are red and yellow in the box, so there is one red and one yellow; except the two tops, they are all yellow, and there are blue and red in the box, so there is one blue and one red. So there is only one red, one blue and one yellow in the box, so the answer is 3;
4.359999=360000-1=600^2-1^2=(600+1)(600-1),
So 359999 is a composite number;
5. Let the middle one be a, then the sum of 1999 consecutive natural numbers = 1999a,
Because a > = 1000, the minimum value of a is 1999,
So the minimum value of the largest number in 1999 is 1999 + 999 = 2998;
6. If you have to redeem 10 yuan every time, you need at least one 5 yuan, two 2 yuan and one 1 yuan, so the answer is 3 × (1 + 2 + 1) = 12

Find all such primes: it is the sum of two primes and the difference of two primes Is there anything else besides five?