If y = - 2Sin (x + φ) (0

If y = - 2Sin (x + φ) (0

(1) On Y-axis symmetry
Replace x with - x, the value of the function remains unchanged
sin(x+φ)=sin(-x+φ)
2sinx * cos φ = 0 for any X
So cos φ = 0
0

For the function y = f (x), X ∈ R, "the image of y = | f (x) | is symmetric about the Y axis" is the result of "y = f (x) is an odd function"______ Conditions

If the image of y = | f (x) | is symmetric about the Y axis, that is, y = | f (x) | is even function, but y = f (x) is not necessarily odd function, for example, y = x2 if y = f (x) is odd function, then y = | f (x) | satisfies | f (- x) | = | - f (x) | = | f (x) |, is even function, and the image of y = | f (x) | is symmetric about the Y axis

Is the image of function y = f (| x |) symmetric about y axis correct

If x = a, the ordinate is f (a), and if x = - A, the ordinate is f (/ - A /) = f (a)