When the rotational speed of the motor is constant, the rotational speed of the driven wheel W is the inverse proportional function of the ratio n of the radius of the driven wheel and the radius of the driving wheel. If the rotational speed of the driving wheel (that is, the motor) is 2800 rpm, the functional relationship between the rotational speed of the driven wheel W and the ratio n of the radius of the driven wheel and the radius of the driving wheel is written, What is the minimum ratio n between the radius of the driven wheel and the radius of the driving wheel?

Give you a formula, you can calculate according to the actual situation. 1, D1 = 1.02 ~ 1.05n2d2 / N1, N1 = n2d2 / 0.95 ~ 0.98, D12, D2 = 0.95 ~ 0.98n1d1 / N2, N2 = n1d1 / 1.02 ~ 1.05, in D2 formula, N1 motor rating

How to calculate the diameter of the driven pulley according to the speed of the motor and the diameter of the pulley?

Let the diameter and rotation speed of the motor pulley (driving pulley) be D1 and N1, and the diameter and rotation speed of the driven pulley D2 and N2. According to the mechanical transmission principle, D2 / D1 = N1 / N2 = I; that is, D2 = D1 * (N1 / N2), the data is substituted into (diameter in mm, commonly used in machining and drawing), D2 = 200 * (1440 / 760) ≈ 378.9mm

The speed of a motor is 1480 rpm, the diameter of the belt pulley is 200 mm, the speed of the driven pulley is 2000 rpm, how many mm is the diameter of the driven pulley?

According to the linear velocity is the same, list the following formula
1480*3.14*200=2000*3.14*D
D=148MM

Working speed △ motor speed = diameter of driving wheel △ diameter of driven wheel × sliding coefficient. How can this be expressed in letters?

n1/n2=d1/d2×μ
N1 is the working speed
N2 is the motor speed
D1 is the diameter of driving wheel
D2 is the diameter of driven wheel
μ is the sliding coefficient (usually 0.98)

The transmission ratio of gear transmission refers to the ratio of driving gear and driven gear to the number of teeth?
Please give an answer to the above question

There are two problems involved here: 1) which is the ratio to which? 2) is the instantaneous transmission ratio or the average transmission ratio? 1) this problem belongs to the definition of transmission ratio. In order to indicate which is the transmission ratio to which, it is usually indicated by the right subscript 12 in the lower right corner of the transmission ratio symbol, that is, the speed ratio of gear 1 to gear 2

What is the driving and driven wheels?
What's the difference between the motion of driving wheel and driven wheel in physics
What's the direction of their movement?

The driving wheel provides power and the driven wheel starts to move due to friction
The direction of motion is the same, but the direction of friction is different
The friction of driving wheel is opposite to the direction of motion, while that of driven wheel is the same

What is the difference and connection between driving wheel and driven wheel?

In the gear train, the driving wheel is the wheel that drives other wheels to rotate, that is, it transmits the power to other wheels. The driven wheel is the wheel that passively rotates and transmits the power from the driving wheel

Steering relationship between driving wheel and driven wheel? Why?

In the case of direct connection, such as gears, friction wheels are in the opposite direction
If it is driven by belt, the direction is the same
It can be analyzed by the interaction of mechanics

On the physics of lever
There is a 2 m lever with a 6kg object at the left end and a 10kg object at the right end. How far should the fulcrum be from the left end to make the lever horizontally balanced? If two kg objects are added at both ends, which side should the fulcrum move to and how much can the lever restore horizontal balance?
Physical format. Explanation or process. Use the formula f1l1 = f2l2 to do (or deformation is also possible)
Speed back. Thank you

It's a matter of moment balance, as long as the moments on both sides are equal
The first question: if the distance between the left and the right fulcrum is L1 and (2-l1), then 6 * L1 = 10 * (2-l1) can solve L1 = 1.25m
Second question: also with this announcement, if the distance between the left end and the fulcrum is L2, then (6 + 2) * L2 = (10 + 2) * (2-l2) can solve L2 = 1.2m, and l2-l1 = -0.05m, so the fulcrum should move 0.05m to the left to make the lever return to horizontal balance. I hope it can help you

Derivative formula for solving physical rate

In the case of X - y trajectory equation, the reciprocal of Y with respect to X is the direction of velocity v
If it is the equation of motion of Y-T, the reciprocal of Y with respect to t is the equation of instant rate with respect to t; from the image, the derivative of a point is the slope of the point, the reciprocal of the point = slope = rate; the displacement change per unit time of the point is explained physically; when Δ t → 0, Δ Y / Δ t = v