Simplification (sin a ^ 2 / cos a + cos a) * cot a

Simplification (sin a ^ 2 / cos a + cos a) * cot a

(sin a^2/cos a +cos a)*cot a
=[（sin²a+cos²a）/cos a]*(cosa/sina)
=1/sina

Simplify [sin (2 π + α)] / [cos (- π - α) cot (π / 2 - α)] =

[sin﹙2π＋α﹚]／[cos﹙﹣π－α﹚cot﹙π／2－α﹚]
=sinα/(-cosα*tanα)
=-tanα/tanα
=-1

How to simplify cos (π - a) sin (A-2 π) / sin (- A - π) cot (π + a)

cos(π-a)=-cosa
sin(a-2π)=-sin(2π-a)=sina
sin(-a-π)=-sin(π+a)=sina
cot(π+a)=cota=cosa/sina
The original form
=-(sinacosa)/(sinacosa/sina)=-sina

Simplification of COS (a - π) cot (5 π - a) / sin (- 2 π - a)

cos(a-π)cot(5π-a)/sin(-2π-a)
=cos(π-a)cot(4π+π-a)/sin(-2π-a)
=-cosacot(π-a)/sin(-a)
=-cosa(-cota)/(-sina)
=-cosa/sina*cota
=-cota*cota
=-cot²a

The value of 2-sin & sup2; 2 + Cos4 under the root sign is

π/2

The result of simplifying 1 + Cos2 α Tan α 2 − cot α 2 is ()
A. -12sin2αB. 12sin2αC. -2sin2αD. 2sin2α

1 + Cos2 α Tan α 2 − cot α 2 = 1 + 2cos2 α − 1sin α 2cos α 2 − cos α 2Sin α 2 = 2cos2 α sin2 α 2 − Cos2 α 2Sin α 2cos α 2 = 2cos2 α − cos α 12sin α = - 12sin2 α

Given that sina = 3 / 5 and a is the second quadrant angle, find the values of cosa and COTA

Cosa = √ 1-sin Λ 2A = 4 / 5
Because the cosine of the second line angle is negative. It's equal to - 4 / 5
COTA = cosa / Sina = - 4 / 3

If (Sina COSA) / (Sina + COSA) = 2, then Tan (a + π / 4) is equal to?

If we divide cosa by both upper and lower, we can get Tana = - 3
Required formula = (Tana + 1) / (1-tana)
We can get the formula equal to - 1 / 2 by directly substituting it
This method is very practical and can be used frequently

It is known that sina = 3 / 5 a? (Wu / 2, Wu). Try to find the value of sin2a and the value of Tan (Wu / 3 + a)

2A is in the middle of 180-360 degrees, so sin2a = 2sinacosa = - 12 / 25, Tana = - 3 / 4,
Tan (60 degree + a) = (tan60 degree + Tana) / (1-tan60 Degree * Tana) = (4 radical 3-3) / (4 + 3 radical 3)

If we know that a is in (Wu / 2, Wu), and Sina = 3 / 5, then the value of Tan (a + Wu / 4) is!
A.7… B.1/7… C.-1/7… D.-7

cosa