Tana is equal to 0.116, what degree is a equal to? Specific degree
tanA=0.116
A=arc tan0.116
(by looking up a table or using a calculator)
A=6° 37‘
Tana = 0.001 how many degrees does a equal?
Please speed up!
This is calculated by arcsine
Because 0.001 is not a special angle, we first find the acute angle when Tan equals 0.001
That is, a = arctan0.001 is about 0.00099999667
Because 0.001 is a positive number and sine is a positive number in the 1 3 quadrant
Therefore, it can be obtained by grasping the acute angle method
When a is in 1 image limit, a = arctan0.001
When a is in three quadrants, a = π + arctan0.001
Sina (180 & # 186; + a) = 1 / 2 a ∈ (- 180 & # 186 / 2,0), then what is Tana equal to
From Sina (180 & # 186; + a) = 1 / 2, we get 180 & # 186; + a = 30 & # 186; + 2K π or 150 & # 186; + 2K π,
If a ∈ (- 180 & # 186 / 2,0), then a = - 30 & # 186;, then Tana = root 3 of minus 3
Given Tana = 2, find (2sina's square + sinacosa's square + cosa's Square) / (4sina's Square - 3cosa's Square)
As above
The original formula = (2Sin & # 178; a + sinacosa + cos & # 178; a) / (4sin & # 178; a-3cos & # 178; a) (the children and the mother are divided by cos & # 178; a.)
=(2tan²a+tana+1)/(4tan²a-3)
=(8+2+1)/(16-3)
=11/13
When Tana = - 2, find 2sina square - sinacosa + cosa square
Hello,
This is a typical Tana type trigonometric function problem
Sin & # 178; a + cos & # 178; a = 1 is the denominator of 2sina square - sinacosa + cosa square,
Then the numerator and denominator are divided by cos & # a
The algebraic expression of Tana
Answer - 11
Hope to help, do not understand can ask, help please adopt
The known Cosa · Tana
First quadrant cosa + Tana+
Second quadrant cosa Tana-
Third quadrant cosa Tana+
The fourth quadrant cosa + Tana - so choose C
Given the angle a ∈ (- Wu / 2,0), cosa = 2 / 3, then Tana=
∵angle a ∈ (- Wu / 2,0)
∴sin a=-√(1-cos² a)=-√5/3
∴tan a=sin a/cos a=(-√5/3)/(2/3)=-√5/2
It is known that a belongs to (π, 3 / 2 π) Tana = 2, cosa =?
A belongs to (π, 3 / 2 π),
So Sina and cosa are both less than 0,
and
1/cos²a=1+tan²a=5,
So cosa = - 1 / √ 5
Finding cosa with known Tana = - 2
Tana = - 2, i.e
sina/cosa=-2.(1)
sin^2a+cos^2a=1.(2)
The two equations are cosa = ± √ 5 / 5
We know Sina + cosa / Sina cosa = 2 and prove that Tana = 3
You have a wrong number
(sinα+cosα)/(sinα-cosα)=2
sinα+cosα=2(sinα-cosα)
sinα+cosα=2sinα-2cosα
sinα=3cosα
sinα/cosα=3
tanα=3