If the focus coordinates of the ellipse are (- 5,0) and (5,0), and the sum of the distances between a point on the ellipse and two focuses is 26, then the equation of the ellipse is () A. x2169+y2144=1B. x2144+y2169=1C. x2169+y225=1D. x2144+y225=1

If the focus coordinates of the ellipse are (- 5,0) and (5,0), and the sum of the distances between a point on the ellipse and two focuses is 26, then the equation of the ellipse is () A. x2169+y2144=1B. x2144+y2169=1C. x2169+y225=1D. x2144+y225=1

∵ the focal coordinates of the ellipse are (- 5,0) and (5,0), the sum of the distances between a point on the ellipse and two focal points is 26, ∵ the focal point of the ellipse is on the x-axis, C = 5, a = 13, ∵ B = A2 − C2 = 12, ∵ the equation of the ellipse is x2169 + y2144 = 1

Given that the ellipse passes through the point (1 / 2,0), and the sum of the distances from any point on the ellipse to two focal points is 2, the standard equation of the ellipse is obtained

From the meaning of the question, 2A = 2, and the ellipse is over (1 / 2,0), so the focus is on the Y axis, and B = 1 / 2. So do it yourself!

It is known that the focal length of an ellipse is 2, and the focal length is the median of the distance between a point on the ellipse and two focal points

C = 1, a = 2, so B ^ 2 = 3
The standard equation is x ^ 2 / 4 + y ^ 2 / 3 = 1

It is known that the focus of the ellipse is on the y-axis, the focal length is 12, and the sum of the distances from a point on the ellipse to two focuses is 20?

2c=12,c=6
2a=20,a=10
So B & # 178; = 100 = 36 = 64
The focus is on the y-axis,
So the equation y & # 178 / 100 + X & # 178 / 64 = 1

It is known that the focus of the ellipse is on the x-axis, the focal length is 8, and the sum of the distances between the points on the ellipse and the two focuses is 10. Find the standard equation of the ellipse!

It is known that the focus of the ellipse is on the x-axis, its focal length is 8, and the sum of the distances from one point to two points on the ellipse is equal to 10

According to the meaning of the title, C = 4, a = 5, so B = 3, so the elliptic equation is 25 parts x square + 6 parts y square = 1

In an ellipse, the chord length passing through the focus and perpendicular to the major axis is the root sign 2, and the distance from the focus to the corresponding guide line is 1

The answer is: the distance from the end point of the string to the focus is 2 / 2 root, the distance from the end point of the string to the guide line is 1, and the eccentricity is the ratio of these two distances, that is, the eccentricity is 2 / 2 root

It is known that the center of the ellipse is at the origin, the focus is on the x-axis, the eccentricity e = root 2 / 2, and the chord length passing through the right focus of the ellipse and perpendicular to the major axis is root 2
(1) Given that the line L and the ellipse intersect at two points a and B, and the distance between the coordinate origin O and the line L is root sign 6 / 3, is the size of ∠ AOB a fixed value? If so, the fixed value can be obtained

The eccentricity e of the center of the ellipse on the x-axis is 2 / 2. The chord length of the right focus tangent perpendicular to the major axis is 2 / 2
Question 1. The standard equation of spherical ellipse. 2. Given that line L and ellipse intersect at PQ, two points o are the origin, and OP is perpendicular to OQ, is the distance between O and line l a fixed value? And find out the fixed value

C / a = e = √ 2 / 2
A = √ 2c, and then we know that (C, √ 2 / 2) is introduced into the elliptic equation on the ellipse, and we get C = 1, B = 1, a = 2
The equation x & sup2; / 2 + Y & sup2; = 1,
Let the linear equation be x = my + N, and (M & sup2; + 2) y & sup2; + 2mny + n & sup2; - 2 = 0
Y1 + y2 = - 2Mn / (M & sup2; + 2) (omitted) fixed value √ 6 / 3

If the center of the ellipse and the two focal points divide the distance between the two guide lines into four equal parts, what is the eccentricity of the ellipse?

From the question meaning: A ^ 2 / C = 2c, we can get a ^ 2 = 2C ^ 2, then e ^ 2 = 1 / 2, so e = √ 2 / 2